Answer:
5.77 Volt
Explanation:
N = 1000, Diameter = 42 cm = 0.42 m, t = 12 ms = 12 x 10^-3 s
Change in magnetic field, B = 5 x 10^-5 T
The peak value of emf is given by
e = N x dФ / dt
e = N x A x dB/dt
e = (1000 x 3.14 x 0.21 x 0.21 x 5 x 10^-5) / (1.2 x 10^-3)
e = 5.77 Volt
Answer:
14.2
Explanation:
find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N
to prevent the sliding she needs to pull horizontally
Fh = 12.3 /Cos 30 =14.2N
suitcase can be pushed to a distance of 0.35 m
Explanation:
Work done= Ff d
w= 670 J
Ff= force of friction
d= distance
force of friction is given by Ff=μ mg
μ= coefficient of friction=2.76
m=mass=71.5 kg
so Ff= (2.76) (71.5) (9.8)
Ff=1934 N
so W= Ff d
670= 1934 d
d=0.35 m
Answer:
The astronaut can throw the hammer in a direction away from the space station. While he is holding the hammer, the total momentum of the astronaut and hammer is 0 kg • m/s. According to the law of conservation of momentum, the total momentum after he throws the hammer must still be 0 kg • m/s. In order for momentum to be conserved, the astronaut will have to move in the opposite direction of the hammer, which will be toward the space station.
Explanation:
The velocity of the block leaving the spring is determined as 18.26 m/s.
<h3>
Velocity of the block</h3>
The velocity of the block leaving the spring is calculated from the principle of conservation of energy.
K.E = Ux
¹/₂mv² = ¹/₂kx²
v² = kx²/m
v² = (500 x 2²)/6
v² = 333.33
v = √333.33
v = 18.26 m/s
Thus, the velocity of the block leaving the spring is determined as 18.26 m/s.
Learn more about velocity here: brainly.com/question/4931057
#SPJ1