Answer:
4.5 g/L.
Explanation:
- To solve this problem, we must mention Henry's law.
- Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
- It can be expressed as: P = KS,
P is the partial pressure of the gas above the solution.
K is the Henry's law constant,
S is the solubility of the gas.
- At two different pressures, we have two different solubilities of the gas.
<em>∴ P₁S₂ = P₂S₁.</em>
P₁ = 525.0 kPa & S₁ = 10.5 g/L.
P₂ = 225.0 kPa & S₂ = ??? g/L.
∴ S₂ = P₂S₁/P₁ = (225.0 kPa)(10.5 g/L) / (525.0 kPa) = 4.5 g/L.
Hope this helps with the answer to your question
Answer:
gvapor or gas to liquid
Explanation:
water which collects as droplets on cold surface when humid air is in contact with it
The balanced equation for the decomposition of hydrogen peroxide is H₂O₂(aq)→2H₂O(l)+O₂(g).
<h3>What is decomposition reaction?</h3>
Decomposition reactions are those reactions in which a compound will decompose into small molecules.
Hydrogen peroxide will decompose into water molecule and oxygen gas, balanced chemical equation will be represented as:
H₂O₂(aq) → 2H₂O(l) + O₂(g)
Where all atoms are present in equal quantities on both side of the equation.
Hence balanced decomposition reaction of H₂O₂ is H₂O₂(aq)→2H₂O(l)+O₂(g).
To know more about decomposition reaction, visit the below link:
brainly.com/question/27300160
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Explanation:
Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.
The reaction is given as:

When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas
The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.
The reaction is given as:

1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid