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katen-ka-za [31]
3 years ago
7

Find the equivalent resistance between points A and B shown in the figure(Figure 1). Consider R1 = 1.9 Ω , R2 = 2.5 Ω , R3 = 4.4

Ω , R4 = 3.5 Ω , R5 = 5.5 Ω , and R6 = 7.1 Ω .
Physics
1 answer:
Luden [163]3 years ago
4 0

The equivalent resistance between the point A and B is 0.95 ohm.

<u>Explanation:</u>

Solving for R3, R4, and R5 since they are in parallel formation. Their equivalent resistance could be

                            1 / R = (1 /R3) + (1 / R4) + (1 / R5)

                                    = (1 / 4.4) + (1 / 3.5) + (1 / 5.5)

                            1 / R = 0.69

                                 R = 1.43 ohm.

Next solving R6 and leg of this resistance which are in series connection,

                                  r = R + R6

                                    = 1.43 + 7.1)

                                  r = 8.53 ohm.

Finally the three resistance R1, R2 and the leg resistance which are in parallel connection,

                              1 / r = (1 / 1.9) + (1 / 2.5) + (1 / 8.53)

                                     = 1.04 ohm

Equivalent resistance R eq = 1 / 1.04 = 0.95 ohm.

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At the local playground, a 21-kg child sits on the right end of a horizontal teeter-totter, 1.8 m from the pivot point. On the l
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Here  k is the spring constant  ,  A is the total displacement of the  the mass  from maximum  compression to maximum extension of the spring

Generally this total mechanical energy is mathematically represented as

        TM  =  KE  + PE

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     PE   = \frac{1}{ 2}  *  k *  [ x ]^2

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=>    \frac{KE}{TM} = 0.75

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