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3 years ago

Anybody want me to follow them on tik tok? plz girls

Physics

2 answers:

IRISSAK [1]3 years ago

8 0

Answer:oop

Explanation:oop

Alina [70]3 years ago

3 0

Nah g i’m chillin. i need sleep tho

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When you throw a ball, the work you do to accelerate it equals the kinetic energy the ball gains. If you do twice as much work w

aniked [119]

Answer:

No. Twice as much work will give the ball twice as much kinetic energy. But since KE is proportional to the speed squared, the speed will be $sqrt{2}$ times larger.

Explanation:

The work done on the ball is equal to the kinetic energy gained by the ball:

$W=K$

So when the work done doubles, the kinetic energy doubles as well:

$2W = 2 K$

However, the kinetic energy is given by

$K=\frac{1}{2}mv^2$

where

m is the mass of the ball

v is its speed

We see that the kinetic energy is proportional to the square of the speed, $v^2$ . We can rewrite the last equation as

$v=\sqrt{\frac{2K}{m}}$

which also means

$v=\sqrt{\frac{2W}{m}}$

If the work is doubled,

$W'=2W$

So the new speed is

$v'=\sqrt{\frac{2(2W)}{m}}=\sqrt{2}\sqrt{\frac{2W}{m}}=\sqrt{2} v$

So, the speed is $\sqrt{2}$ times larger.

5 0

3 years ago

A 0.119 kg ball is dropped from rest. if the magnitude of the ball's momentum is 0.817 kg·m/s just before it lands on the ground

NemiM [27]

I am not good at math but what grade r u in cause i am in 9th and if u r then i might can help

8 0

3 years ago

The final stages of a star's life depend on its mas. true or false?

Diano4ka-milaya [45]

Answer:

TRUE

Explanation:

Low mass stars last lots longer.

5 0

3 years ago

A particle (m = 4.3 × 10^-28 kg) starting from rest, experiences an acceleration of 2.4 × 10^7 m/s^2 for 5.0 s. What is its de B

Novay_Z [31]

Answer:

Wavelength, $\lambda=1.28\times 10^{-14}\ m$

Explanation:

Given that,

Mass of the particle, $m=4.3\times 10^{-28}\ kg$

Acceleration of the particle, $a=2.4\times 10^7\ m/s^2$

Time, t = 5 s

It starts from rest, u = 0

The De Broglie wavelength is given by :

$\lambda=\dfrac{h}{mv}$

v = a × t

$\lambda=\dfrac{h}{mat}$

$\lambda=\dfrac{6.67\times 10^{-34}}{4.3\times 10^{-28}\times 2.4\times 10^7\times 5}$

$\lambda=1.28\times 10^{-14}\ m$

Hence, this is the required solution.

4 0

3 years ago

PLS ANSWER FAST WILL MARK BRAINLIEST

densk [106]

In position A

The mirror has to be observed in the ray reflected from the mirror.

Since the the angle of reflection is equal to the angle of incidence, the reflected ray must be in equal path as the incident ray.

That phenomenon is only in diagram A

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3 years ago