All categories

3 years ago

What type of forces must the polar water molecules break to dissolve ethanol, C2H5OH?

Chemistry

1 answer:

ANTONII [103]3 years ago

5 0

Answer:

Option B

Covalent Bonding

Explanation:

Covalent bonds in C2H5OH are formed between the carbon and hydrogen atoms, where there are shared electron pairs.

This is a weak form of attraction that holds the C2H5OH molecule together, and can easily be broken by a polar solvent such as water.

In order for water to be able to dissolve the C2H5OH molecule, it must break the covalent bonding present in the molecule

You might be interested in

What is a quantum of light energy called?

kirill115 [55]

Answer:

A) photon

Explanation:

hope it helps and give brainliest if its correct

4 0

1 year ago

Read 2 more answers

Does anyone know o I'm correct? If not what's the answer?

igomit [66]

I believe it means idea because a Web is out line to a a more structured idea

6 0

3 years ago

Explain how a substances flammability can indicate a chemical change.

Marat540 [252]

Answer:

This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May I have brainliest please? :)

4 0

2 years ago

The Brahman cattle have good resistance to high temperature, but its meat is poor and tough to eat. The English shorthorn cattle

N76 [4]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers

The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate con

Aloiza [94]

Use the formula for second order reaction:

$\frac{1}{C} = \frac{1}{C_0} + kt$

C = concentration at time t
C0 = initial conc.
k = rate constant
t = time

1st equation : $\frac{1}{0.56} = \frac{1}{C_0} + 115k$

2nd Equation: $\frac{1}{0.033} = \frac{1}{C_0} + 735k$

Find $\frac{1}{C_0}$ from 1st equation and put it in 2nd equation:

$\frac{1}{0.033} = \frac{1}{0.56} - 115k + 735k$

$\frac{1}{0.033} - \frac{1}{0.56} = 620k$

k = 0.046

3 0

3 years ago