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Talja [164]
3 years ago
10

The dimerization of butadiene 2C4H61 g2h C8H121 g2 was studied at 500. K, and the following data were obtained: Time (s) [C4H6]

(mol/L) 195 1.6 3 1022 604 1.5 3 1022 1246 1.3 3 1022 2180 1.1 3 1022 6210 0.68 3 1022 Assuming that Rate 52 D3C4H64 Dt determine the form of the rate law, the integrated rate law, and the value of the rate constant for this reaction.
Chemistry
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

Rate law: k[C_4H_6]^2

Integrated Rate Law: \frac{1}{[C_4H_6]}=\frac{1}{[C_4H_6]_0}+kt

k = 1.4 \times 10^{-2}

Explanation:

We can see that the graph of time is linear compared to \frac{1}{[C_4H_6]} and the reaction is second order hence we get the rate law from k[A]^n.

The integrated rate law for second order is \frac{1}{[A]}=\frac{1}{[A]_0} +kt where A is C_4H_6.

The slope of the graph \frac{1}{[C_4H_6]} w.r.t time is equal to k. The slope of the graph from the table is 0.014 which is equal to k.

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A 1.555-g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. Refer to Example Exercise 14.l and show the calc
Sunny_sXe [5.5K]

Answer:

a) 101%

b)59.7%

Explanation:

The equation for the thermal decomposition of baking soda is shown;

2NaHCO3 → Na2CO3 + H2O + CO2

Number of moles of baking soda= mass/molar mass= 1.555g/84.007 g/mol = 0.0185 moles

From the reaction equation;

2 moles of baking soda yields 1 mole of sodium carbonate

0.0185 moles of baking soda will yield = 0.0185 moles ×1 /2 = 9.25 ×10^-3 moles of sodium carbonate.

Therefore, mass of sodium carbonate= 9.25 ×10^-3 moles × 106gmol-1= 0.9805 g of sodium carbonate. This is the theoretical yield of sodium carbonate.

%yield = actual yield/theoretical yield ×100

% yield = 0.991/0.9805 ×100

%yield = 101%

Since ;

2NaHCO3 → Na2CO3 + H2O + CO2

And H2O + CO2 ---> H2CO3

Hence I can write, 2NaHCO3 → Na2CO3 + H2CO3

Molar mass of H2CO3= 62.03 gmol-1

Molar mass of baking soda= 84 gmol-1

Therefore, mass of baking soda=

0.325/62.03 × 2 × 84 = 0.88 g of NaHCO3

% of NaHCO3= 0.88/1.473 × 100 = 59.7%

7 0
2 years ago
a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?
victus00 [196]

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

Molarity = Mass conc.(g/L) / molar Mass

Molarity = 45.33/100 = 0.4533mol/L

7 0
3 years ago
A gas at 300 k and 4.0 atm is moved to a new loacation with a temperature of 250 k. The volume changes from 5.5 L to 2.0 L. What
alexgriva [62]
Answer is: <span>the pressure of the gas is 9,2 atm.
</span>p₁ = 4,0 atm.
T₁ = 300 K.
V₁ = 5,5 L.
p₂ = ?
T₂ = 250 K.
V₂ = 2,0 L.
Use combined gas law - the volume of amount of gas is proportional to the ratio of its Kelvin temperature and its pressure.<span> 
</span>p₁V₁/T₁ = p₂V₂/T₂.
4 atm · 5,5 L ÷ 300 K  = p₂ · 2,0 L ÷ 250 K.
0,0733 = 0,008p₂.
p₂ = 9,2 atm.

4 0
3 years ago
Which material is a mixture 1 water 2 air 3 methane 4 magnesium
amm1812

Answer: Air

Explanation: Pure air is a mixture of several gases that are invisible and odorless. Consists of 78% nitrogen, 21% oxygen, and less than 1% of argon, carbon dioxide.

8 0
2 years ago
Henri draws a wave that has a 4 cm distance between the midpoint and the trough. Geri draws a wave that has an 8 cm
OLga [1]

Answer:

I'm thinking Henri's wave and Geri's wave have the same amplitude and energy, but i'm not %100 sure

Explanation:

8 0
3 years ago
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