Answer:
1) Se2O5
2) I2O6
3)Zn3n2
4) Cr(HCO3)3
Explanation:
selenium pentaoxide (= also called diselenium pentoxide)
= Se2O5
⇒ Se = 78.97 g/mol
⇒ O = 16 g/mol
⇒ 2*78.97 + 5*16 = 237.94 g/mol
iodine trichloride
= I2O6
⇒ I = 126.9 g/mol
⇒ Cl = 35.45 g/mol
⇒ 2* 126.9 + 6 * 35.45 = 466.5 g/mol
zinc (1) nitride does not exist (it's Zinc(ii)nitride
The oxidation number for zinc is always 2
Zn3n2
⇒ Zn = 65.38 g/mol
⇒ N = 14 g/mol
⇒3*65.38 + 2* 14 = 224.14 g/mol
chromium (III) bicarbonate
Cr(HCO3)3
⇒ Cr = 52 g/mol
⇒ H = 1.01 g/mol
⇒ C = 12 g/mol
⇒ O = 16 g/mol
52 + 3*1.01 + 3*12 + 6*16 = 235.03 g/mol
We can solve this problem using Raoults law. The formula
for Raoults law is:
P_a = X_a * P
where,
P_a = the partial pressure of substance A
X_a = the mole fraction of substance A
P = total pressure
Therefore calculating for P:
P = P_a / X_a
P = 0.580 atm / 0.35
<span>P = 1.657 atm</span>
Answer:
Definitely not. This is because the alkaline earth metal [basically group 2 elements] are reactive and will react with the contents of the can, contaminating it.
Answer:
option b is correct
as it have same number of atoms on both the reactant and product side.
