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amm1812
3 years ago
15

Suppose that you lift four boxes individually, each at a constant velocity. The boxes have weights of 18 N, 6.0 N, 9.0 N, and 12

N, and you do 36 J of work on each. Match each box to the vertical distance through which it is lifted. 2.0 m
Physics
1 answer:
cricket20 [7]3 years ago
4 0

Explanation:

It is known that the relation between work and force is as follows.

              w = F \times d cos (\theta)

where,    \theta = angle between the applied force and direction of movement of the object which is zero in this case. As, cos (0) = 1.

Therefore,    d = \frac{w}{F}

(i)   For w = 36 J, and F = 9 N then value of d will be as follows.

                    d = \frac{w}{F}

                       = \frac{36 J}{9 N}

                       = 4 m

(ii)  For w = 36 J, and F = 12 N then value of d will be as follows.

                    d = \frac{w}{F}

                       = \frac{36 J}{12 N}

                       = 3 m

(iii)  For w = 36 J, and F = 6 N then value of d will be as follows.

                    d = \frac{w}{F}

                       = \frac{36 J}{6 N}

                       = 6 m

(iv)  For w = 36 J, and F = 18 N then value of d will be as follows.

                    d = \frac{w}{F}

                       = \frac{36 J}{18 N}

                       = 2 m

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