Question

Suppose that you lift four boxes individually, each at a constant velocity. The boxes have weights of 18 N, 6.0 N, 9.0 N, and 12 N, and you do 36 J of work on each. Match each box to the vertical distance through which it is lifted. 2.0 m

Answer 1

Explanation:

It is known that the relation between work and force is as follows.

              w = $F \times d cos (\theta)$

where,    $\theta$ = angle between the applied force and direction of movement of the object which is zero in this case. As, cos (0) = 1.

Therefore,    d = $\frac{w}{F}$

(i)   For w = 36 J, and F = 9 N then value of d will be as follows.

                    d = $\frac{w}{F}$

                       = $\frac{36 J}{9 N}$

                       = 4 m

(ii)  For w = 36 J, and F = 12 N then value of d will be as follows.

                    d = $\frac{w}{F}$

                       = $\frac{36 J}{12 N}$

                       = 3 m

(iii)  For w = 36 J, and F = 6 N then value of d will be as follows.

                    d = $\frac{w}{F}$

                       = $\frac{36 J}{6 N}$

                       = 6 m

(iv)  For w = 36 J, and F = 18 N then value of d will be as follows.

                    d = $\frac{w}{F}$

                       = $\frac{36 J}{18 N}$

                       = 2 m