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Alinara [238K]
3 years ago
10

For a particular redox reaction NO is oxidized to NO3– and Ag is reduced to Ag. Complete and balance the equation for this react

ion in basic solution. Phases are optional.
Chemistry
2 answers:
mote1985 [20]3 years ago
6 0

It has been given that,

NO + Ag⁺ → NO₃⁻ + Ag

The oxidation half reaction is,

NO + Ag⁺ = NO₃⁻ + Ag

The reduction half reaction is,

Ag⁺ +e⁻ → Ag

The overall balanced reaction is:

3Ag⁺ + NO + 2H₂O → 3Ag + NO₃⁻

Cerrena [4.2K]3 years ago
3 0

Answer:

NO(g) + 2H2O(l) + 3Ag^+(aq)---------> NO3^-(aq) + 4H^+(aq) + 3Ag

Explanation:

Oxidation half equation

NO(g) + 2H2O(l)--------> NO3^-(aq) + 4H^+(aq). + 3e

Reduction half equation

3Ag^+(aq) + 3e--------> 3Ag

Overall reaction equation

NO(g) + 2H2O(l) + 3Ag^+(aq)---------> NO3^-(aq) + 4H^+(aq) + 3Ag

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Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
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Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

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The flask will bust.

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Limestone (CaCO₃) is the second most abundant mineral on Earth after SiO₂. For many uses, it is first decomposed thermally to qu
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Limestone (CaCO₃) is the second most abundant mineral on Earth after SiO₂. For many uses, it is first decomposed thermally to quicklime (CaO). MgO is prepared similarly from MgCO₃.

AT 871°C CaCO 3 needs about 1 hour for complete decomposition.

<h3>At what temperature Caco3 decompose to Cao?</h3>

At any temperature higher than 835°C, the value of Δ G ∘ will be negative and the decomposition reaction will be spontaneous.

AT 871°C CaCO 3 needs about 1 hour for complete decomposition.

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