Answer:
It contains 6.02*10^23 molecules
Explanation:
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Answer:
The hypothetical van't Hoff factor of magnesium nitrate,
is <u>3 .</u>
Explanation:
Lets calculate -
We know that ,
Dissociation should be 100% for the hypothetical vant hoff factor , that is
and 
for
Therefore , putting the given values ,
<u>Hence , the answer is 3.</u>
Answer:
sorry this is a kind of confusing question.
Explanation:
Answer:it will be c on edg 2021
Explanation:
Answer:
10.5L
Explanation:
The volume in this question can be calculated by using the formula for gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the provided information in this question:
P = 6.18 atm
V = ?
n = 2.35 moles
R = 0.0821 Latm/molK
T = 63°C = 63 + 273 = 336K
Using PV = nRT
V = nRT/P
V = 2.35 × 0.0821 × 336/ 6.18
V = 64.83/6.18
V = 10.49
V = 10.5L
