Ask question

Ask question

All categories

3 years ago

7

The same mass, with a new string, is whirled in a vertical circle of the same radius about a fixed point. Find the magnitude of

the tension when the mass is at the top if its speed at the top is 7.77 m/s.

1 answer:

Masteriza [31]3 years ago

7 0

Answer:

256.3 N

Explanation:

Throughout the motion of the mass in the circular motion, the resultant of the Tension in the string and the weight of the body gives the net force (centripetal force) that is responsible for the acceleration of the mass in a circular motion.

At the top of the vertical circle of the motion of the mass, the tension is directed downwards towards the centre of the circle and the weight also is directed downwards towards the earth.

Net force = ma = T + W

ma = T + mg

But a = (v²/r) for circular motion,

(mv²)/r = T + mg

m = 2.31 kg

v = 7.77 m/s

r = 0.500 m

g = acceleration due to gravity = 9.8 m/s²

(2.31×7.77²)/0.5 = T + (2.31×9.8)

278.923 = T + 22.638

T = 278.923 - 22.638

T = 256.285 N = 256.3 N

Hope this Helps!!!

You might be interested in

A student conducts an experiment to test how the temperature affects the amount of sugar that can dissolve in water. In the expe

ZanzabumX [31]

B. The temperature of the water.

The independent variable is the variable that is changed to affect the dependent variable. In this instance, the temperature of the water is being changed to affect the amount of sugar that dissolves.

6 0

3 years ago

Which variables are involved in understanding Kepler's third law of motion? (1 point)

Zielflug [23.3K]

The variables which are involved in understanding Kepler's third law of

motion are

Orbital velocity

Distance to sun

<h3 /><h3>What is Kepler's third law of motion?</h3>

Kepler's third law of motion states that the the square of the orbital period of

a planet is proportional to the cube of the semi-major axis of its orbit. He

also inferred that the greater the distance, the slower the orbital velocity.

This thereby makes option D the most appropriate option as it contains the

orbital velocity and distance to sun variables.

Read more about Kepler's third law of motion here brainly.com/question/777046

7 0

2 years ago

Read 2 more answers

The maximum distance from the Earth to the Sun (at aphelion) is 1.521 1011 m, and the distance of closest approach (at perihelio

LUCKY_DIMON [66]

Answer:

29274.93096 m/s

$2.73966\times 10^{33}\ J$

$-5.39323\times 10^{33}\ J$

$2.56249\times 10^{33}\ J$

$-5.21594\times 10^{33}$

Explanation:

$r_p$ = Distance at perihelion = $1.471\times 10^{11}\ m$

$r_a$ = Distance at aphelion = $1.521\times 10^{11}\ m$

$v_p$ = Velocity at perihelion = $3.027\times 10^{4}\ m/s$

$v_a$ = Velocity at aphelion

m = Mass of the Earth = 5.98 × 10²⁴ kg

M = Mass of Sun = $1.9889\times 10^{30}\ kg$

Here, the angular momentum is conserved

$L_p=L_a\\\Rightarrow r_pv_p=r_av_a\\\Rightarrow v_a=\frac{r_pv_p}{r_a}\\\Rightarrow v_a=\frac{1.471\times 10^{11}\times 3.027\times 10^{4}}{1.521\times 10^{11}}\\\Rightarrow v_a=29274.93096\ m/s$

Earth's orbital speed at aphelion is 29274.93096 m/s

Kinetic energy is given by

$K=\frac{1}{2}mv_p^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(3.027\times 10^{4})^2\\\Rightarrow K=2.73966\times 10^{33}\ J$

Kinetic energy at perihelion is $2.73966\times 10^{33}\ J$

Potential energy is given by

$P=-\frac{GMm}{r_p}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.471\times 10^{11}}\\\Rightarrow P=-5.39323\times 10^{33}$

Potential energy at perihelion is $-5.39323\times 10^{33}\ J$

$K=\frac{1}{2}mv_a^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(29274.93096)^2\\\Rightarrow K=2.56249\times 10^{33}\ J$

Kinetic energy at aphelion is $2.56249\times 10^{33}\ J$

Potential energy is given by

$P=-\frac{GMm}{r_a}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.521\times 10^{11}}\\\Rightarrow P=-5.21594\times 10^{33}$

Potential energy at aphelion is $-5.21594\times 10^{33}\ J$

6 0

3 years ago

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

konstantin123 [22]

Answer:

$I=2.71\times 10^{-5}\ A$

Explanation:

A 6.0-cm-diameter parallel-plate capacitor has a 0.46 mm gap.

What is the displacement current in the capacitor if the potential difference across the capacitor is increasing at 500,000V/s?

Let given is,

The diameter of a parallel plate capacitor is 6 cm or 0.06 m

Separation between plates, d = 0.046 mm

The potential difference across the capacitor is increasing at 500,000 V/s

We need to find the displacement current in the capacitor. Capacitance for parallel plate capacitor is given by :

$C=\dfrac{A\epsilon_o}{d}\\\\C=\dfrac{\pi r^2\epsilon_o}{d}$ , r is radius

Let I is the displacement current. It is given by :

$I=C\dfrac{dV}{dt}$

Here, $\dfrac{dV}{dt}$ is rate of increasing potential difference

So

$I=\dfrac{\pi r^2\epsilon_o}{d}\times \dfrac{dV}{dt}\\\\I=\dfrac{\pi (0.03)^2\times 8.85\times 10^{-12}}{0.46\times 10^{-3}}\times 500000\\\\I=2.71\times 10^{-5}\ A$

So, the value of displacement current is $2.71\times 10^{-5}\ A$ .

4 0

3 years ago

Which of these processes are chemical reactions

White raven [17]

Explanation:

In chemical reactions, chemical changes occur.
Atoms are simply rearranged and new bonds are formed.
Chemical reactions are driven by a need for atoms to attain stability in their structure.
In all chemical reactions, a reactant or reactants gives new product i.e new substances are formed.
Most these reactions are not easily reversible.
They are usually accompanied by the release of energy.

Learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

5 0

3 years ago