Determine the static pressure to stagnation pressure ratio associated with the following motion in standard air: (a) a runner mo
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Answer: 1.98 × 10^4 N
Explanation:
Form similar triangle ADE and ABC
a/x= 2/3, a=2/3x
Width of the strip w= 2(4+a) = 8+2a
W= 8 +2 (2/3x)= 8+4/3x
Area of the strip = w Δx
(8 +4/3x) Δx
Pressure on the strip p= pgx= 10^3 ×9.81x= 9810x
But,
Force= Pressure × area= 9810x × (8+4/3x)Δx
Adding the forces and taking lim n to infinity
F total= lim n--> infinity E 9810x × (8+4/3x)Δx
Ftotal= Integral 2,0 9810x × (8+4/3x)Δx
F total= 9810 integral 2, 0 (8+4/3x)dx
= 9810(8+x^2/2 + 4/3x^3/3)2,0
=9810(4x^2 + 4/9x^3)
=9810(4x2^2 + 4/9×2^3-0)
=9810(16 + 32/9)
Hydrostatic force as an integral
Ft= 19.18 ×10^4N
Answer:
The mass in:
1) Grams =
2) Kilograms =
3)Tonnes =
4) Megatonnes =
Explanation: The given mass of the aircraft in pounds is 833,000 pounds.
Part 1)
Since we know that 1 pound equals 453.5 grams thus by ratio we have
833,000 pounds =
Part 2)
Since we know that 1000 grams equals 1 kilogram
thus the above mass in kilograms equals
Part 3)
Since there are 1000 kilograms in 1 tonne
thus the given mass is converted into tonnes as
Part 4)
Since 1 Mega tonne(Mton) equals 1000 tonnes thus the given mass is converted into mega tonnes as