Answer:
A
Explanation:
The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:
More precisely, the strength of the field at a distance r from the centre of the sphere is
where k is the Coulomb's constant and Q is the charge on the sphere.
From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.
This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.
The answer is C. 15 meters North
Displacement is the distance and direction from the origin. If you move 20 meters North, your displacement is 20 meters North. If you move 5 meters South, you are basically moving back the way you came by 5 meters, which means you are now 15 meters North.
I hope this helped! :)
Answer:
When a bridge is used for long time It lises its elastic .Therefore ,the amount of strain in the bridge for a given stress will become large and ultimately, the bridge may collapse .This is why the bridge are declared unsafe after a long time.
Explanation:
<h3><u>Answer;</u></h3>
= 2868 Newtons
<h3><u>Explanation;</u></h3>
Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.
Centripetal force is given by the formula;
mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;
mass = 65 kg, velocity = 15 m/s and r = 5.1 m
Therefore;
Centripetal force = (65 × 15²)/ 5.10
= 2867.65 Newtons
= 2868 N
Answer:
the apparent weight of the astronaut is 81.032 N { towards moon }
Explanation:
Given that;
Mass of astronaut m = 80 kg
Distance of spaceship from the Earth's moon r = 2200 km = 2200 × 10³ m
Acceleration due to gravity of the moon = GM/r²
where M is mass of the moon( 7.34767309 × 10²² kg )
gravitational constant G = 6.67 × 10⁻¹¹
So,
Acceleration due to gravity of the moon g is;
g = [ (6.67 × 10⁻¹¹) × (7.35 × 10²²) ] / (2200 × 10³)²
g = 4.90245 × 10¹² / 4.84 × 10¹²
g = 1.0129 m/s²
now, we take the positive direction towards the moon if the spacecraft is moving with constant velocity, a = 0
The apparent weight is measured by the normal force FN
so,
∑F = ma
-FN + mg = ma
-FN + mg = 0
FN = mg
we substitute
FN = 80 × 1.0129
FN = 81.032 N { towards moon }
Therefore, the apparent weight of the astronaut is 81.032 N { towards moon }