The <span>tendency of the standard reduction potential of an element is to be reduced and is based on the measurement of volts at standard conditions. The more positive the standard potential of an element, the more it is reduced</span>
Answer:
See the answer below
Explanation:
If the root of a plant grows away from the pull of earth's gravity, <u>it will not produce any effect on the plant provided that other conditions of growth are kept normal.</u>
<em>According to research, the force of the Earth's gravity has no effect on the growth features of plants. Plants that were grown away from the influence of gravity still grew normally in a research conducted in space by NASA in 2010.</em>
This thus means that the upward growth of the stem and the downward growth of the root in a negative and positive response to gravity respectively is dictated by the inherent attributes of plants themselves, and not by the force of the earth's gravity.
A.
<span>hydrogen; helium
is the right answer</span>
Answer:
El reactivo limite es
y la cantidad de urea producida es 881.58 g
Explanation:
Podemos empezar con la reacción:
![2NH_3~+~CO_2~->~(NH_2)_2CO~+~H_2O](https://tex.z-dn.net/?f=2NH_3~%2B~CO_2~-%3E~%28NH_2%29_2CO~%2B~H_2O)
Tenemos 2 átomos de nitrógeno en ambos lados, 1 átomo de carbono en ambos lados, 2 átomos de oxigeno en ambos lados y 6 átomos de hidrógeno en ambos lados. Por lo tanto <u>la reacción esta balanceada</u>.
Ahora, para hallar el reactivo limite necesitamos seguir los <u>siguientes pasos:</u>
1) <u>Convertir a moles</u> usando la masa molecular de cada compuesto ( 17 g/mol para el amoniaco y 28 g/mol para el dióxido de carbono).
2) Usando el la relación molar entre cada compuesto con la urea podemos <u>calcular las moles de urea</u> ( para el amoniaco la relación es 2:1 y para el dióxido de carbono la relación es 1:1).
3) Finalmente, usando la masa molar de la urea (60 g/mol) podemos <u>calcular la masa de urea</u>.
![500~g~NH_3\frac{1~mol~NH_3}{17~g~NH_3}\frac{1~mol~(NH_2)_2CO}{2~mol~NH_3}\frac{60~g~(NH_2)_2CO}{1~mol~(NH_2)_2CO}=881.58~g~(NH_2)_2CO](https://tex.z-dn.net/?f=500~g~NH_3%5Cfrac%7B1~mol~NH_3%7D%7B17~g~NH_3%7D%5Cfrac%7B1~mol~%28NH_2%29_2CO%7D%7B2~mol~NH_3%7D%5Cfrac%7B60~g~%28NH_2%29_2CO%7D%7B1~mol~%28NH_2%29_2CO%7D%3D881.58~g~%28NH_2%29_2CO)
![1000~g~CO_2\frac{1~mol~CO_2}{28~g~CO_2}\frac{1~mol~(NH_2)_2CO}{1~mol~CO_2}\frac{60~g~(NH_2)_2CO}{1~mol~(NH_2)_2CO}=1364.6~g~(NH_2)_2CO](https://tex.z-dn.net/?f=1000~g~CO_2%5Cfrac%7B1~mol~CO_2%7D%7B28~g~CO_2%7D%5Cfrac%7B1~mol~%28NH_2%29_2CO%7D%7B1~mol~CO_2%7D%5Cfrac%7B60~g~%28NH_2%29_2CO%7D%7B1~mol~%28NH_2%29_2CO%7D%3D1364.6~g~%28NH_2%29_2CO)
El elemento que tiene la <u>menor cantidad de urea</u> se da en el calculo del amoniaco. <u>Por lo tanto, el reactivo limite es el amoniaco y la cantidad de urea producida es 881.58 g</u>
Espero que sea de ayuda!
Conservation of mass is the underlying principle of balancing equation. When we balance equation, this means that we acknowledge that before and after the chemical reaction, the elements are conserved. To balance the chemical equation, we add coefficients before each reactant and product. Here are the following answers:
Reaction 1:
<span>2Al
3ZnCl2
3Zn
2AlCl3
Reaction 2:
</span><span>4NH3
3O2
2N2
6H2O</span>