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3 years ago

The material that has very strong adhesive properties is: a. PVC b. HDPE c. UHMWPE d. Epoxy e. Bakelite

Chemistry

1 answer:

LiRa [457]3 years ago

5 0

Answer:

d. Epoxy

Explanation:

Adhesion or adhesive properties of a substance is the property that allows bonding of dissimilar materials if necessary. Adhesives may have high cohesive strength or a low cohesive strength.

PVC "glue" is usually a solvent for plastic components and these are different type of PVC glues. They function well on plastics.

HDPE - is known as High-density polyethylene or polyethylene high-density is a thermoplastic polymer in short it is what we know as plastic bags or nylon produced from the monomer ethylene. HDPE is not an adhesive

UHMWPE - is known as Ultra-high-molecular-weight polyethylene (UHMWPE, UHMW) is a subset of the thermoplastic polyethylene. Also known as high-modulus polyethylene, (HMPE). UHMWPE is not an adhesive.

An epoxy adhesive is a copolymer adhesive formed by mixing together a resin and a hardener. There are some special epoxies however don't require a hardener, but are activated by heat instead. Others epoxies hardening strength may degrade in under exposure to ultraviolet light or high heat. Adhesives such as epoxies have many different uses. Epoxy may be used on metal, glass, plastic, rubber, fiberglass and fiberglass-reinforced plastic (FRP).

Bakelite or polyoxybenzylmethylenglycolanhydride isn't an adhesive and it was the first plastic made from synthetic components.

Epoxy however has very strong adhesive properties because of the varieties of substances it can bring to together.

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3 years ago

How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? Express your answer numerically in moles. View Availabl

VladimirAG [237]

Answer:

A) 8.00 mol NH₃

B) 137 g NH₃

C) 2.30 g H₂

D) 1.53 x 10²⁰ molecules NH₃

Explanation:

Let us consider the balanced equation:

N₂(g) + 3 H₂(g) ⇄ 2 NH₃(g)

Part A

3 moles of H₂ form 2 moles of NH₃. So, for 12.0 moles of H₂:

$12.0molH_{2}.\frac{2molNH_{3}}{3molH_{2}} =8.00molNH_{3}$

Part B:

1 mole of N₂ forms 2 moles of NH₃. And each mole of NH₃ has a mass of 17.0 g (molar mass). So, for 4.04 moles of N₂:

$4.04molN_{2}.\frac{2molNH_{3}}{1molN_{2}} .\frac{17.0gNH_{3}}{1molNH_{3}} =137gNH_{3}$

Part C:

According to the <em>balanced equation</em> 6.00 g of H₂ form 34.0 g of NH₃. So, for 13.02g of NH₃:

$13.02gNH_{3}.\frac{6.00gH_{2}}{34.0gNH_{3}} =2.30gH_{2}$

Part D:

6.00 g of H₂ form 2 moles of NH₃. An each mole of NH₃ has 6.02 x 10²³ molecules of NH₃ (Avogadro number). So, for 7.62×10⁻⁴ g of H₂:

$7.62 \times 10^{-4} gH_{2}.\frac{2molNH_{3}}{6.00gH_{2}} .\frac{6.02\times 10^{23}moleculesNH_{3} }{1molNH_{3}}=1.53\times10^{20}moleculesNH_{3}$

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3 years ago

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tankabanditka [31]

Answer:

The answer is true.

Explanation:

Hello! Let's solve this!

The answer is true.

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