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4 years ago

The material that has very strong adhesive properties is: a. PVC b. HDPE c. UHMWPE d. Epoxy e. Bakelite

Chemistry

1 answer:

LiRa [457]4 years ago

5 0

Answer:

d. Epoxy

Explanation:

Adhesion or adhesive properties of a substance is the property that allows bonding of dissimilar materials if necessary. Adhesives may have high cohesive strength or a low cohesive strength.

PVC "glue" is usually a solvent for plastic components and these are different type of PVC glues. They function well on plastics.

HDPE - is known as High-density polyethylene or polyethylene high-density is a thermoplastic polymer in short it is what we know as plastic bags or nylon produced from the monomer ethylene. HDPE is not an adhesive

UHMWPE - is known as Ultra-high-molecular-weight polyethylene (UHMWPE, UHMW) is a subset of the thermoplastic polyethylene. Also known as high-modulus polyethylene, (HMPE). UHMWPE is not an adhesive.

An epoxy adhesive is a copolymer adhesive formed by mixing together a resin and a hardener. There are some special epoxies however don't require a hardener, but are activated by heat instead. Others epoxies hardening strength may degrade in under exposure to ultraviolet light or high heat. Adhesives such as epoxies have many different uses. Epoxy may be used on metal, glass, plastic, rubber, fiberglass and fiberglass-reinforced plastic (FRP).

Bakelite or polyoxybenzylmethylenglycolanhydride isn't an adhesive and it was the first plastic made from synthetic components.

Epoxy however has very strong adhesive properties because of the varieties of substances it can bring to together.

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3 years ago

14. 60. g of NaOH is dissolved in enough distilled water to make 300 mL of a stock solution. What volumes of this solution and d

zepelin [54]

The question is incomplete, the complete question is attached below.

Answer : The volumes of stock solution and distilled water will be, 20 mL and 80 mL respectively.

Explanation : Given,

Mass of NaOH = 60 g

Volume of stock solution = 300 mL

Molar mass of NaOH = 40 g/mol

First we have to calculate the molarity of stock solution.

$\text{Molarity}=\frac{\text{Mass of }NaOH\times 1000}{\text{Molar mass of }NaOH\times \text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Molarity}=\frac{60g\times 1000}{40g/mole\times 300mL}=5mole/L=5M$

Now we have to determine the volume of stock solution and distilled water mixed.

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution.

From data (A) :

$M_1=5M\\V_1=20mL\\M_2=1M\\V_2=?$

Putting values in above equation, we get:

$5M\times 20mL=1M\times V_2\\\\V_2=100mL$

Volume of stock solution = 20 mL

Volume of distilled water = 100 mL - 20 mL = 80 mL

From data (B) :

$M_1=5M\\V_1=20mL\\M_2=1M\\V_2=?$

Putting values in above equation, we get:

$5M\times 20mL=1M\times V_2\\\\V_2=100mL$

Volume of stock solution = 20 mL

Volume of distilled water = 100 mL - 20 mL = 80 mL

From data (C) :

$M_1=5M\\V_1=60mL\\M_2=1M\\V_2=?$

Putting values in above equation, we get:

$5M\times 60mL=1M\times V_2\\\\V_2=300mL$

Volume of stock solution = 60 mL

Volume of distilled water = 300 mL - 60 mL = 240 mL

From data (D) :

$M_1=5M\\V_1=20mL\\M_2=1M\\V_2=?$

Putting values in above equation, we get:

$5M\times 60mL=1M\times V_2\\\\V_2=300mL$

Volume of stock solution = 60 mL

Volume of distilled water = 300 mL - 60 mL = 240 mL

From this we conclude that, when 20 mL stock solution and 80 mL distilled water mixed then it will result in a solution that is approximately 1 M NaOH.

Hence, the volumes of stock solution and distilled water will be, 20 mL and 80 mL respectively.

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