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ryzh [129]
3 years ago
6

A load of 36 N attached to a spring hanging

Physics
1 answer:
givi [52]3 years ago
3 0

Answer:

The required force is 55.38 N.

Explanation:

First we have to find the spring constant K;

                         k = \frac{mg}{d} = \frac{36}{0.065} = 553.846 N/m

As,

                         F= -Kx

                   or, F=  - 553.846 × 0.10

                   or, F=  -55.3846 N

Hence,

                  F_{needed} = - F_{spring}

            ∴  F_{needed} = 55.38 N

The required force  to stretch it by this  amount is 55.38 N.  

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