Force and distance are used to calculate work. Work is measured in which unit? joules watts newtons meters
1 answer:
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Answer:
(a) the mechanical energy of the system, U = 0.1078 J
(b) the maximum speed of the object, Vmax = 0.657 m/s
(c) the maximum acceleration of the object, a_max = 15.4 m/s²
Explanation:
Given;
Amplitude of the spring, A = 2.8 cm = 0.028 m
Spring constant, K = 275 N/m
Mass of object, m = 0.5 kg
(a) the mechanical energy of the system
This is the potential energy of the system, U = ¹/₂KA²
U = ¹/₂ (275)(0.028)²
U = 0.1078 J
(b) the maximum speed of the object
(c) the maximum acceleration of the object
Answer:
You must add 8cm of water to the tank
Explanation:
In order to find how much the height is we will use the Snell Refraction law
.
This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:
Then we will find the refraction angle relative to the vertical this way:
Then, theta2=32.12°
Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:
Then, X=18.8cm, we can approximate it to 19cm
Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm
Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:
Then, Y=38cm
In this case, you must add 8cm of water to the tank to move the beam on the bottom 5cm