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Answer:
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Explanation:
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It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.
A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.
Assume the initial concentration is 1.00 mol/L. Then,
The concentration drops to one-fourth of its initial value in two half-lives.
∴ Time = 2 × 16.7 s = 33.4 s
The theoretical yield of silver chloride, AgCl is 5.2109 g
The balanced equation for the reaction is given below:
<h3>3AgNO₃(aq) + AICI₃(aq) —> Al(NO₃)₃ (aq) + 3AgCl (s) </h3>Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:
Molar mass of AICI₃ = 133.34 g/mol
Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g
Molar mass of AgCl = 143.32 g/mol
Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>
<h3>SUMMARY</h3>From the balanced equation above,
133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.
Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:
From the balanced equation above,
133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.
Therefore,
1.616 g of AICI₃ will react to produce = = 5.2109 g of AgCl.
Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g
Learn more: brainly.com/question/24653699