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goblinko [34]
3 years ago
8

Consider a rectangular wing mounted in a low-speed subsonic wind tunnel. The wing model completely spans the test-section, so th

at the flow "sees" essentially an infinite wing. The wing has a NACA 23012 airfoil section and a chord of 0.23 m, where the lift on the entire wing is measured as 200 N by the wind tunnel force balance. Determine the angle of attack if the wing span, airflow pressure, temperature, and velocity are 2 m, 1 atm, 303 K, and 42 m/s, respectively. Refer to the Appendix graphs given below for standard values. (Round the final answer to the nearest whole number.)
Physics
1 answer:
Ksivusya [100]3 years ago
3 0

Answer:

Answer for the question :

"Consider a rectangular wing mounted in a low-speed subsonic wind tunnel. The wing model completely spans the test-section, so that the flow "sees" essentially an infinite wing. The wing has a NACA 23012 airfoil section and a chord of 0.23 m, where the lift on the entire wing is measured as 200 N by the wind tunnel force balance. Determine the angle of attack if the wing span, airflow pressure, temperature, and velocity are 2 m, 1 atm, 303 K, and 42 m/s, respectively. Refer to the Appendix graphs given below for standard values" is in the attachment.

Explanation:

Download pdf
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Answer:

B. 22,22,23,23,22,22,23

Explanation:

The standard deviation is a measure of dispersion or variability of a data set. In order to determine the data set that has the smallest standard deviation, we shall investigate on the ranges of the data sets given. The range of a data set is simply the difference between the maximum and minimum values in a data set. A data set that has a smaller range also has a smaller standard deviation.

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Answer:

FB = 0.187 N

Explanation:

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Due to B depends on "y" you take into account the contribution of each element dy of the wire to the magnitude of the magnetic force. Thus, you have to integrate the following expression:

|\vec{F_B}|=Isin\theta\int_0^{0.25}B(y)dy=Isin\theta\int_0^{0.25}(0.5y)dy\\\\|\vec{F_B}|=(2.0*10^{-3}A)(sin36.86\°)(0.5T)[\frac{0.25^2}{2}m]=0.187\ N

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Answer: See explanation

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