Question

A boy of mass 45kg sits 109cm to the left of seesaw. Another boy of mass 29000g wants to balance the seesaw. At what distance he needs to sit?

Answer 1

Answer:

$d_{2}$ = 169 cm

Explanation:

Mass 1 = 45 kg   => Force = 450 N

Mass 2 = 29 kg   => Force = 290 N

According to principle of moments:

=> $F_{1}d_{1} = F_{2}d_{2}$

Where $F_{1}$ = 450 N, $d_{1}$ = 109 cm and $F_{2}$ = 290 N

=> (450)(109) = 290$d_{2}$

=> 49050 =  290$d_{2}$

Dividing both sides by 290

=> $d_{2}$ = 169 cm