Answers:
a) ![T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}](https://tex.z-dn.net/?f=T_%7B2%7D%3ET_%7B5%7D%3ET_%7B1%7D%3ET_%7B3%7D%3DT_%7B6%7D%3ET_%7B4%7D)
b) ![a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}](https://tex.z-dn.net/?f=a_%7B4%7D%3Ea_%7B6%7D%3Ea_%7B1%7D%3Ea_%7B3%7D%3Ea_%7B5%7D%3Ea_%7B2%7D)
Explanation:
a) Since we are told the satellites circle the space station at constant speed, we can assume they follow a uniform circular motion and their tangential speeds
are given by:
(1)
Where:
is the angular frequency
is the radius of the orbit of each satellite
is the period of the orbit of each satellite
Isolating
:
(2)
Applying this equation to each satellite:
(3)
(4)
(5)
(6)
(7)
(8)
Ordering this periods from largest to smallest:
![T_{2}>T_{5}>T_{1}>T_{3}=T_{6}>T_{4}](https://tex.z-dn.net/?f=T_%7B2%7D%3ET_%7B5%7D%3ET_%7B1%7D%3ET_%7B3%7D%3DT_%7B6%7D%3ET_%7B4%7D)
b) Acceleration
is defined as the variation of velocity in time:
(9)
Applying this equation to each satellite:
(10)
(11)
(12)
(13)
(14)
(15)
Ordering this acceerations from largest to smallest:
![a_{4}>a_{6}>a_{1}>a_{3}>a_{5}>a_{2}](https://tex.z-dn.net/?f=a_%7B4%7D%3Ea_%7B6%7D%3Ea_%7B1%7D%3Ea_%7B3%7D%3Ea_%7B5%7D%3Ea_%7B2%7D)
Answer: a and d
Explanation: A.) the power lines themselves
B.) the wooden pole that supports the lines
C.) the rubber soles on the worker’s boots
D.) the metal tools the worker uses
E.) the wooden ladder leaning against the lines
Answer:
32000 N
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 40 m/s
Distance (s) = 10 m
Final velocity (v) = 0 m/s
Mass (m) of car = 400 Kg
Force (F) =?
Next, we shall determine the acceleration of the the car. This can be obtained as follow:
Initial velocity (u) = 40 m/s
Distance (s) = 10 m
Final velocity (v) = 0 m/s
Acceleration (a) =?
v² = u² + 2as
0² = 40² + (2 × a × 10)
0 = 1600 + 20a
Collect like terms
0 – 1600 = 20a
–1600 = 20a
Divide both side by –1600
a = –1600 / 20
a = –80 m/s²
The negative sign indicate that the car is decelerating i.e coming to rest.
Finally, we shall determine the force needed to stop the car. This can be obtained as follow:
Mass (m) of car = 400 Kg
Acceleration (a) = –80 m/s²
Force (F) =?
F = ma
F = 400 × –80
F = – 32000 N
NOTE: The negative sign indicate that the force is in opposite direction to the motion of the car.
Answer:
The pressure difference will increase by the factor of 1.75
Explanation:
For constant flow rate, coefficient of viscosity, length of the vessel and the pressure difference is inversely proportional to the fourth power of the radius of the blood vessel
Apply the principle of Poiseuille’s law.
Q = (P2 - P1)/R
Pls check the attached file for step by step solution of the question. It is submitted in this way as typing the equation may not be explanatory.
Acceleration = (change in speed) / (time for the change) = 9/3 = <em>3 m/s²</em> .
His mass makes no difference.