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Sav [38]
3 years ago
7

How many valence electrons are in the chemical Hafnium?

Chemistry
2 answers:
suter [353]3 years ago
5 0
4 Electrons g because i just had it rs
djverab [1.8K]3 years ago
4 0

Answer:

Their are 4 electrons just had the same problem

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Predict which of the substances, NH3, N2, CH2Cl2, Cl2, CCl4 has
gulaghasi [49]

Answer:

djsjwjwjdjxjdbs djwuqidx8diw d xbd

6 0
3 years ago
When lithium nitride, Li 3 N ( s ) , is treated with water, H 2 O ( l ) , ammonia, NH 3 ( g ) , is produced. Predict the formula
allochka39001 [22]

Answer : The formula of the gas produced is, PH_3 (phosphine gas)

Explanation :

According to the question, when sodium phosphide is treated with water then it react to give phosphine gas and sodium hydroxide.

The balanced chemical reaction will be:

Na_3P(aq)+3H_2O(l)\rightarrow PH_3(g)+3NaOH(aq)

By Stoichiometry of the reaction we can say that:

1 mole of sodium phosphide reacts with 3 moles of water to give 1 mole of phosphine gas and 3 moles of sodium hydroxide.

Thus, the formula of the gas produced is, PH_3 (phosphine gas)

8 0
2 years ago
When a chemical reaction occurs, what happens to the atoms of the two substances?
marta [7]

Answer:

In a chemical reaction, only the atoms present in the reactants can end up in the products. No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

8 0
2 years ago
Read 2 more answers
The anion formed from an oxygen atom is called a(n)
marta [7]
A. Oxygen ion
I am not sure but that's the right one I think. If I am wrong then I am sorry
6 0
3 years ago
33.56 g of fructose (C6H,206) and 18.88 g of water are mixed to obtain a 40.00 ml solution a. What is this solution's density? b
Darina [25.2K]

Explanation:

Mass of fructose = 33.56 g

Mass of water =  18.88  g

Total mass of the solution =  Mass of fructose + Mass of water = M

M = 33.56 g + 18.88  g =52.44 g

Volume of the solution = V = 40.00 mL

Density =\frac{Mass}{Volume}

a) Density of the solution:

\frac{M}{V}=\frac{52.44 g}{40.00 mL}=1.311 g/mL

b) Molar mass of fructose = 180.16 g/mol

Moles of fructose = n_1=\frac{ 33.56 g}{180.16 g/mol}=0.1863 mol

Molar mass of water = 18.02 g/mol

Moles of water= n_2=\frac{ 18.88 g}{18.02 g/mol}=1.0477 mol

Mole fraction of fructose in this solution:\chi_1

\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1863 mol}{0.1863 mol+1.0477 mol}

\chi_1=0.1510

Mole fraction of water = \chi_2=1-\chi_1=0.8490

c) Average molar mass of of the solution:

=\chi_1\times 180.16 g/mol+\chi_2\times 18.02 g/mol

=0.1510\times 180.16 g/mol+0.8490\times 18.02 g/mol=42.50 g/mol

d) Mass of 1 mole of solution = 42.50 g/mol

Density of the solution = 1.311 g/mL

d) Specific molar volume of the solution:

\frac{\text{Average molar mass}}{\text{Density of the mass}}

=\frac{42.50 g/mol}{1.311 g/mL}=32.42 mL/mol

5 0
3 years ago
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