Question

Hypothetically, if you weighed out 0.8036 g of NaOH, what would the exact NaOH solution concentration be

Answer 1

Complete question

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Answer:

The value is $C = 0.02009 \ M$

Explanation:

From the question we are told that

The mass of NaOH is $m= 0.8036 g$

In the question DI (stands for de-ionized water )

So the number of moles of NaOH present in the given mass is

$n = \frac{m}{Z}$

Here Z is the molar mass of NaOH with value $Z = 40 \ g/ mol$

So

$n = \frac{0.8036}{40}$

$n =0.02009 \ mols$

Given that the volume of the flask is V = 1 L then we can evaluated the concentration as

$C = \frac{n}{V}$

=>    $C = \frac{0.02009}{1}$

=>    $C = 0.02009 \ M$