Answer:
Explanation:
An object begins from rest and accelerates at a rate of 2.5 meters ... at a rate of +1.6 meters per second' while traveling +5.0 ... Calculate the block's rate of acceleration. 4. Vf² V, ²+2 ad. (12 m/s)?-(Omis) + 2(a)(50m) ... represents the motion of a car during a 6.0 second time interval. ... A cat moves 15 meters east in 5 seconds.
Answer:
114.44 J
Explanation:
From Hook's Law,
F = ke................. Equation 1
Where F = Force required to stretch the spring, k = spring constant, e = extension.
make k the subject of the equation
k = F/e.............. Equation 2
Given: F = 10 lb = (10×4.45) N = 44.5 N, e = 4 in = (4×0.254) = 1.016 m.
Substitute into equation 2
k = 44.5/1.016
k = 43.799 N/m
Work done in stretching the 9 in beyond its natural length
W = 1/2ke²................. Equation 3
Given: e = 9 in = (9×0.254) = 2.286 m, k = 43.799 N/m
Substitute into equation 3
W = 1/2×43.799×2.286²
W = 114.44 J
In order to fabricate a uniform wire that has a resistance of R = 0.500Ω from 1.00 g of copper and all the copper is to be used, the Length, L of the copper required is 1.82m.
<h3>What would be the length of the copper wire?</h3>
The length of the wire is obtained as follows:
Length, L = √R*m/e*d
where;
R is resistance and is equal to 0.50 Ω
m is mass of the copper and is equal to 1.00 g or 10⁻³ kg
e, resistivity of Copper = 1.7 x 10⁻⁸ Ω⁻¹m
density of copper, d = 8.92 x 10³ kg/m³
L = √(10⁻³ * 0.50/1.7 x 10⁻⁸ * 8.92 x 10³)
Length, L= 1.82m
In conclusion, the length of the wire is obtained from the mass and density of the copper wire.
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