Answer:
49.09 moles of gas are added to the container
Explanation:
Step 1: Data given
Initial volume = 3.10 L
Number of moles gas = 9.51 moles
The final volume = 19.1 L
The pressure, temperature remain constant
Step 2: Calculate number of moles gas
V1/n1 = V2/n2
⇒with V1 = the initial volume of the gas = 3.10 L
⇒with n1 = the initial number of moles = 9.51 moles
⇒with V2 = the increased volume = 19.1 L
⇒with n2 = the final number of moles gas
3.10L / 9.51 moles = 19.1 L / n2
n2 = 58.6 moles
The new number of moles is 58.6
Step 3: calculate the number of moles gas added
Δn = 58.6 - 9.51 = 49.09 moles
49.09 moles of gas are added to the container
Answer:
a
No
b
100 mm Hg
Explanation:
From the question we are told that
The vapor pressure of CHCl3, is 
The temperature of CHCl3 is 
The volume of the container is 
The temperature of the container is 
The mass of CHCl3 is m = 0.380 g
Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as

Here M is the molar mass of CHCl3 with the value 
=> 
=>
Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as

Here R is the gas constant with value 
So
Given that the number of moles of CHCl3 evaporated is less than the number of moles of CHCl3 initially present , then it mean s that not all the liquid evaporated
At equilibrium the temperature of CHCl3 will be equal to the pressure of air so the pressure at equilibrium is 100 mmHg
The
correct answer is A. In the combined gas law, if the volume is decreased and
the pressure is constant, then the temperature decreases.
<span>P1V1/
T1 = P2V2 / T2</span>
<span>Assume
the volume decrease by half; V2 = V1/2</span>
<span>P1V1/
T1 = P2V1 /2 T2</span>
<span>Cancelling
terms,</span>
<span>1/T1
= 1/2 T2</span>
T2
= T1/2
<span>Thus,
the temperature decreased.</span>
Answer:
Gallium is silvery white and soft enough to be cut with a knife. It takes on a bluish tinge because of superficial oxidation. Unusual for its low melting point (about 30 °C [86 °F]), gallium also expands upon solidification and supercools readily, remaining a liquid at temperatures as low as 0 °C (32 °F).