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3 years ago

An organized set of investigation procedures is called a

Physics

1 answer:

Oduvanchick [21]3 years ago

7 0

Answer:

An organized set of investigation procedures is called a scientific method.

There are five steps of the scientific method for an experiment.

Step 1: Make a question

Step 2: Do some research for that question.

Step 3: Hypothesis ( a guess what might happen during the experiment)

Step 4: Test and collect data

Step 5: Conclusion ( what you learned from the experiment)

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What happen when a star dies?

Vera_Pavlovna [14]

It depends on the size of the star. If it's size was normal then it cools down into White dwarf, then a black dwarf. If a really huge star dies, then we can see a "Supernova" from that.

Hope this helps!!

7 0

3 years ago

A 1.20-m cylindrical rod of diameter 0.570 cm is connected to a power supply that maintains a constant potential difference of 1

nasty-shy [4]

(a) $1.72\cdot 10^{-5} \Omega m$

The resistance of the rod is given by:

$R=\rho \frac{L}{A}$ (1)

where

$\rho$ is the material resistivity

L = 1.20 m is the length of the rod

A is the cross-sectional area

The radius of the rod is half the diameter: $r=0.570 cm/2=0.285 cm=2.85\cdot 10^{-3} m$ , so the cross-sectional area is

$A=\pi r^2=\pi (2.85\cdot 10^{-3} m)^2=2.55\cdot 10^{-5} m^2$

The resistance at 20°C can be found by using Ohm's law. In fact, we know:

- The voltage at this temperature is V = 15.0 V

- The current at this temperature is I = 18.6 A

So, the resistance is

$R=\frac{V}{I}=\frac{15.0 V}{18.6 A}=0.81 \Omega$

And now we can re-arrange the eq.(1) to solve for the resistivity:

$\rho=\frac{RA}{L}=\frac{(0.81 \Omega)(2.55\cdot 10^{-5} m^2)}{1.20 m}=1.72\cdot 10^{-5} \Omega m$

(b) $8.57\cdot 10^{-4} /{\circ}C$

First of all, let's find the new resistance of the wire at 92.0°C. In this case, the current is

I = 17.5 A

So the resistance is

$R=\frac{V}{I}=\frac{15.0 V}{17.5 A}=0.86 \Omega$

The equation that gives the change in resistance as a function of the temperature is

$R(T)=R_0 (1+\alpha(T-T_0))$

where

$R(T)=0.86 \Omega$ is the resistance at the new temperature (92.0°C)

$R_0=0.81 \Omega$ is the resistance at the original temperature (20.0°C)

$\alpha$ is the temperature coefficient of resistivity

$T=92^{\circ}C$

$T_0 = 20^{\circ}$

Solving the formula for $\alpha$ , we find

$\alpha=\frac{\frac{R(T)}{R_0}-1}{T-T_0}=\frac{\frac{0.86 \Omega}{0.81 \Omega}-1}{92C-20C}=8.57\cdot 10^{-4} /{\circ}C$

5 0

3 years ago

Which of the following IS NOT a part of an electromagnet?

Agata [3.3K]

I'd go with electricity source. Good luck!!

3 0

3 years ago

1 .

son4ous [18]

Answer:

Find answers below.

Explanation:

1. Radiant: the energy of light.

2. Light: makes it possible to see things.

3. Sun: a source of light. This source of light is referred to as solar energy and it's renewable source of energy.

4. Crest: top of wave. Thus, it's typically the highest part of an electromagnetic wave.

5. Trough: bottom of wave. Thus, it's typically the lowest part of an electromagnetic wave.

6. Wavelength: distance from one point on one wave to the same point on the next wave.

7. Infrared light: it has longer wavelengths than visible light.

8. X-rays: shorter wavelengths than visible light.

Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.

An electromagnetic spectrum refers to a range of frequency and wavelength that an electromagnetic wave is distributed or extends. The electromagnetic spectrum comprises of gamma rays, visible light, ultraviolet radiation, x-rays, radio waves, and infrared radiation.

3 0

3 years ago

Solve each of these problems, remembering to include formula, calculations, and units!

KATRIN_1 [288]

Answer:

I nEeD heLp

Explanation:

HelP

5 0

3 years ago