Solve for acceleration:
<em>a</em> = (21.4 m/s - 33.8 m/s) / (4.7 s)
<em>a</em> ≈ -2.6 m/s²
Solve for force:
<em>F</em> = (1400 kg) <em>a</em> ≈ -3700 N
The minus sign tells you the force points in the opposite direction of the car's motion. Its magnitude is always positive, so <em>F</em> = 3700 N.
The appropriate expression for the calculation of power by relating the angular energy in a given time.
In other words the instantaneous power of an angular accelerating body is the torque times the angular velocity

Where
Torque
Angular speed
Our values are given by


The angular velocity must be transformed into radians per second then


Replacing,



The average power delivered by the engine at this rotation rate is 211.1kW
Answer:
33 N
Explanation:
v = Velocity of fluid = 8+2 = 10 m/s
= Density of fluid = 1.2 kg/m³
C = Coefficient of drag = 1.1
A = Cross sectional area = 0.5 m²
Drag force is given by

The drag force on the athlete is 33 N
Answer:
Height h= 1.7 m
Explanation:
Supposing we have to find height in meter.
1 feet = 0.3048 m
1 inch = 0.0254 m
Given that:
5 feet
= 5×0.3048
= 1.524 m
and 7 inch = 7×0.0254= 0.1778 m
Therefore total height of a man in meter
5 feet 7 inch = 1.5424+0.1778 =1.7 m
Height h= 1.7 m