Question

A ball is dropped from mystery height and it accelerates at 8m/s/s and it takes .9 seconds to hit the ground what is the height of the drop ?

Answer 1

Answer:

The height of the drop is 3.24 m.

Explanation:

As the ball is dropped from a mystery height and it takes 0.9 seconds to hit the ground with the acceleration of 8 m/s2. Then the velocity with which the ball is thrown can be determined as

$Velocity=Acceleration*Time$

As the acceleration is 8 m/s2 and time is 0.9 s. Then

$Velocity = 8*0.9=7.2 m/s$

So we know, the velocity u = 7.2 m/s , acceleration a = 8 m/s2 and time taken to reach the ground as t = 0.9 s. Thus, the height of the drop will be equal to the displacement of the ball from the top to the ground. Thus with the help of second equation of motion, we can determine the height as height will be equal to displacement (s).

$s=ut+\frac{1}{2}at^{2}$

Thus,

$s=(7.2*0)+(\frac{1}{2}*8*(0.9)^{2})=3.24 m$

Thus, the height of the drop will be 3.24 m.