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andreev551 [17]
3 years ago
6

What is controlled based on readings from the air quality​ sensors?

Engineering
1 answer:
babymother [125]3 years ago
5 0

Answer:

sorry i dont understand the answer

Explanation:

this is a xd f question

i think that the a :The dehumidifier set point and function will be not functonal is the xf is not as smooth as the other quality sensors and the The amount of outside air used in the system would be unecssary as the LP2 is not functonal as the 8f4 do The heating coil set point and function would be the correct answer for the l60

  • ff i think this question is for adults and im only 13
  • concluisoin 667 i think bats are strong
  1. im so bored of covi.d 19
  2. coclusion : i would rather be at home cause school is very boring

\left \{ {{y=2} \atop {x=2}} \right. \leq \\ \geq \int\limits^a_b {x} \, dx x^{2} x^{2} x^{2} \sqrt{x} \neq  \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \sqrt{x} \sqrt{x} \sqrt{x} \sqrt[n]{x} \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \alpha \frac{x}{y} \frac{x}{y} \frac{x}{y} x_{123} \beta \neq \geq

this is my conluion that the indices of area 62 is a postive alkaline but a negative result due to the fact that we have pullotion

plz say thanks to this answer ive been righting for like a hour now lol

anyway i want to be a mechanical engineer when i grow up ; hopefully that will be very soon

but they dont get that much money

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<u>Option-(A)</u>

Explanation:

<u>Typical applications for the high carbon steels includes the following;</u>

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The diameter of an extruder barrel = 85 mm and its length = 2.00 m. The screw rotates at 55 rev/min, its channel depth = 8.0 mm,
babunello [35]

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Qx = 9.109.10^5 \times 10^{-6} m³/s  

Explanation:

given data

diameter = 85 mm

length = 2 m

depth = 9mm

N = 60 rev/min

pressure p = 11 × 10^6 Pa

viscosity n = 100 Pas

angle = 18°

so  Qd will be

Qd = 0.5 × π² ×D²×dc × sinA × cosA   ..............1

put here value and we get

Qd = 0.5 × π² × ( 85 \times 10^{-3} )²× 9  \times 10^{-3}  × sin18 × cos18

Qd = 94.305 × 10^{-6} m³/s

and

Qb = p × π × D × dc³ × sin²A ÷  12  × n × L    ............2

Qb = 11 × 10^{6} × π × 85 \times 10^{-3}  × ( 9  \times 10^{-3} )³ × sin²18 ÷  12  × 100 × 2

Qb = 85.2 × 10^{-6} m³/s

so here

volume flow rate Qx = Qd - Qb   ..............3

Qx =  94.305 × 10^{-6}  - 85.2 × 10^{-6}  

Qx = 9.109.10^5 \times 10^{-6} m³/s  

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3 years ago
When is a handrail required for stairs?
Leviafan [203]

Answer:

after 8 stepshddnffuddbnggkbdbkloyr

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