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Taya2010 [7]
3 years ago
9

Please help.. This is not a test.. It’s a Naked egg experiment.. please help

Chemistry
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

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How many total atoms are found in one molecule of alpo4?
Kruka [31]
There is 1 aluminium atom and 4 polonium atoms
5 0
4 years ago
What is the pH of a solution that has a [H+] = 0.010 mol/L?
Serjik [45]

Answer:

pH = 2

A 0.010 M solution of hydrochloric acid, HCl, has a molarity of 0.010 M. This means that [H+] = 1 x 10-2 M. The pH of this aqueous solution of H+ ions is pH = 2

hope this helps :3

Download pdf
5 0
2 years ago
Which reaction shows decomposition?
Nina [5.8K]

Answer:

I think first one..........

6 0
3 years ago
Write the balanced equation and determine the information requested in each of the following.
Elena L [17]

Answer:

See explanation.

Explanation:

Hello!

In this case, we can proceed as follows:

1. Here, the undergoing chemical reaction is:

C_2H_2+\frac{5}{2} O_2\rightarrow 2CO_2+H_2O

Thus, the moles and mass of water turn out:

n_{H_2O}=20.0kgC_2H_2*\frac{1000gC_2H_2}{1kgC_2H_2} *\frac{1molC_2H_2}{26.04gC_2H_2} *\frac{1molH_2O}{1molC_2H_2}=768molH_2O\\\\m_{H_2O}=768molH_2O*\frac{18.02gH_2O}{1molH_2O}=13,840 gH_2O

2. Here, the undergoing chemical reaction is:

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

So the required moles of HCl and the yielded of water are:

n_{CaCO_3}=2.6molHCl*\frac{1molCaCO_3}{2molHCl}=1.3molCaCO_3\\\\ n_{H_2O}=2.6molHCl*\frac{1molH_2O}{2molHCl}=1.3molH_2O

3. Here, the undergoing chemical reaction is:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

Now, we apply each mole ratio obtain:

A.

n_{H_2SO_4}=2.6molAl_2O_3*\frac{3molH_2SO_4}{1molAl_2O_3} =7.8molH_2SO_4

B.

n_{Al_2(SO_4)_3}=2.6molAl_2O_3*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3} =2.6molAl_2(SO_4)_3

Best regards!

4 0
3 years ago
Assign oxidation numbers to each element in this compound. NO
algol13

<u>Answer:</u>

NO ---> N +2 and O -2

<u>Explanation:</u>

Oxidation numbers are assigned to the elements of a compound to keep a track of the number of electrons each atom has.

Here we have a compound NO (Nitrogen Oxide). The Nitrogen is assigned an oxidation number of +2 while Oxygen in this compound is assigned an oxidation number of -2.

So the algebraic sum of the oxidation numbers of the elements in the compound NO is equal to zero.

5 0
3 years ago
Read 2 more answers
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