Producing energy is the answer
Answer: 17.6×10^-3g of CO2
Explanation:
We first look at the stoichiometry of the balanced reaction equation. One mole of methane produces one mole of carbon dioxide. Hence 16g of methane yields 44g of carbon dioxide. If we now composed this with the given 6.40×10^-3g of methane as shown in the solution attached, we obtain the answer stated above.
La levigación es el proceso de moler una sustancia insoluble en un polvo fino, mientras está húmedo. El material se introduce en el molino junto con agua, en la cual la sustancia en polvo permanece suspendida, y fluye del molino como un líquido turbio o una pasta delgada, de acuerdo con la cantidad de agua empleada.
Divide the number by 6.02 x 10^23 so the measurement is in moles and multiply by 22.4 to convert it into liters
Here amount of HCl can be calculated as:
As concentration of HCl= 1 M or 1 mol L
Volume of HCl= 75mL=0.075L
So number of moles of HCl will be= 0.075\times 1
number of moles of HCl will be= 0.075 mol
As we see from the equation,
Mg (s) + 2HCl (aq)------->H₂ (g) + MgCl₂ (aq)
That 2 moles of HCl will produce 1 mole of H₂
So 0.075 mol of HCl will produce 0.038 mole of H₂
