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Anettt [7]
3 years ago
8

Why is it important to cut all the way through an electrical wire on the first try?

Engineering
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

I always thought it was so that the older wire could not have a problem and have another electrician must come back and fix it.

Explanation:

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A 50-lbm iron casting, initially at 700o F, is quenched in a tank filled with 2121 lbm of oil, initially at 80o F. The iron cast
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a) The final equilibrium temperature is 83.23°F

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See attached workings

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Sharon is designing a house in an area that receives a lot of rainfall all year. Which material should she use to stick the wood
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A car accelerates from rest with an acceleration of 5 m/s^2. The acceleration decreases linearly with time to zero in 15 s, afte
Tpy6a [65]

Answer: At time 18.33 seconds it will have moved 500 meters.

Explanation:

Since the acceleration of the car is a linear function of time it can be written as a function of time as

a(t)=5(1-\frac{t}{15})

a=\frac{d^{2}x}{dt^{2}}\\\\\therefore \frac{d^{2}x}{dt^{2}}=5(1-\frac{t}{15})

Integrating both sides we get

\int \frac{d^{2}x}{dt^{2}}dt=\int 5(1-\frac{t}{15})dt\\\\\frac{dx}{dt}=v=5t-\frac{5t^{2}}{30}+c

Now since car starts from rest thus at time t = 0 ; v=0 thus c=0

again integrating with respect to time we get

\int \frac{dx}{dt}dt=\int (5t-\frac{5t^{2}}{30})dt\\\\x(t)=\frac{5t^{2}}{2}-\frac{5t^{3}}{90}+D

Now let us assume that car starts from origin thus D=0

thus in the first 15 seconds it covers a distance of

x(15)=2.5\times 15^{2}-\farc{15^{3}}{18}=375m

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v(15)=5\times 15-\frac{15^{2}}{6}=37.5m/s

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Thus the total time it requires equals 15+3.33 seconds

t=18.33 seconds

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2 years ago
What are the benefits of using the engineering design process? combining scientific knowledge and creativity in a rigid and stru
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combining scientific knowledge, careful reasoning, and artistic invention in a flexible approach to problem-solving

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