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Lostsunrise [7]
3 years ago
14

Make a report on the different types of effects of forces acting on an object

Physics
1 answer:
frez [133]3 years ago
8 0

Explanation:

According to newtons first law of motion " A body is at a state of rest or uniform motion unless acted upon by a force (external)" which will either

1. change the direction

2. change the acceleration

3. change the velocity(moves or stop the body from moving)

4. change the shape or size

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5 0
3 years ago
A bicycle is ridden along a horizontal road with a driving force of 400, n,400n. its speed is constant at 12, m, slash, s,12m/s.
mr_godi [17]

The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.

<h3>What is friction force?</h3>

The friction force is the opposing force which acts on the object which is in relative motion.

The driving force is equal and opposite to the friction force acting between road and bicycle.

Friction force = 400N

The friction force between rider and bike is zero.

So the magnitude of sum of friction force = 400N +0 = 400N

Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.

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4 0
2 years ago
With manual transmission, use your right foot for the brake and accelerator and left foot for the clutch true or false
GaryK [48]

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4 0
3 years ago
Read 2 more answers
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
calculate the kinetic energy of a car with a mass of 500kg traveling at a velocity of 10m/s^2 north. A) 2,500j B) 25,000j C) 50,
Arte-miy333 [17]
The correct answer would be A) 2,500j
8 0
3 years ago
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