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inn [45]
3 years ago
15

Universal Containers has a junction object called "Job Production Facility". With 2 master-detail relationships to the Job and P

roduction Facility custom objects. Both master records have a private sharing model. What statement is true if a user's profile allows access (Create/Read) to the Job, but no access to the Production Facility Object?
Engineering
1 answer:
alexdok [17]3 years ago
3 0

Answer:

C. The user will not be able to see the junction object records or the field values.

Explanation:

For the profile of the user to give access permission such as create and read to the job without granting access permission to the production facility object, the value of the field or records of the junction object will not be seen by the user. This is one of the necessary criteria or principle for the universal container with a junction object.

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Write two scnr.nextInt statements to get input values into birthMonth and birthYear. Then write a statement to output the month,
aalyn [17]

Answer:

import java.util.Scanner;

public class InputExample {

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       int birthMonth;

       int birthYear;

       birthMonth = scnr.nextInt();

       birthYear = scnr.nextInt();

       System.out.println(birthMonth+"/"+birthYear);

   }

}

3 0
3 years ago
In an experiment, the local heat transfer over a flat plate were correlated in the form of local Nusselt number as expressed by
zvonat [6]

Answer:

R= 1.25

Explanation:

As given the local heat transfer,

Nu_x = 0.035 Re^{0.8}_x Pr^{1/3}

But we know as well that,

Nu=\frac{hx}{k}\\h=\frac{Nuk}{x}

Replacing the values

h_x=Nu_x \frac{k}{x}\\h_x= 0.035Re^{0.8}_xPr^{1/3} \frac{k}{x}

Reynolds number is define as,

Re_x = \frac{Vx}{\upsilon}

Where V is the velocity of the fluid and \upsilon is the Kinematic viscosity

Then replacing we have

h_x=0.035(\frac{Vx}{\upsilon})^{0.8}Pr^{1/3}kx^{-1}

h_x=0.035(\frac{V}{\upsilon})^{0.8}Pr^{1/3}kx^{0.8-1}

h_x=Ax^{-0.2}

<em>*Note that A is just a 'summary' of all of that constat there.</em>

<em>That is A=0.035(\frac{V}{\upsilon})^{0.8}Pr^{1/3}k</em>

Therefore at x=L the local convection heat transfer coefficient is

h_{x=L}=AL^{-0.2}

Definen that we need to find the average convection heat transfer coefficient in the entire plate lenght, so

h=\frac{1}{L}\int\limit^L_0 h_x dx\\h=\frac{1}{L}\int\limit^L_0 AL^{-0.2}dx\\h=\frac{A}{0.8L}L^{0.8}\\h=1.25AL^{-0.2}

The ratio of the average heat transfer coefficient over the entire plate  to the local convection heat transfer coefficient is

R = \frac{h}{h_L}\\R= \frac{1.25Al^{-0.2}}{AL^{-0.2}}\\R= 1.25

3 0
3 years ago
What is the step in which you are testing your hypothesis ​
jonny [76]

Answer:

Step 1: State your null and alternate hypothesis. ...

Step 2: Collect data. ...

Step 3: Perform a statistical test. ...

Step 4: Decide whether the null hypothesis is supported or refuted. ...

Step 5: Present your findings.

8 0
2 years ago
. A two-dimensional fluid motion is represented by a point vortex of strength Γ set at distance c from an infinite straight soli
Lostsunrise [7]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

8 0
3 years ago
Section BreakProblem 08.048 2.value: 5.00 pointsRequired information Problem 08.048.b Compute the expected error. The expected e
Lady_Fox [76]

Answer:

a) 19 or select the closest answer

b) 5%

Explanation:

a)

from the voltage divide rule

V_{in} = V_0 * \frac{R_2}{R_2 + R_f}

\frac{V_0}{V_{in}} = \frac{R_2 + R_f}{R_2} => 1 + \frac{R_f}{R_2} = 20

\frac{R_f}{R_2} = 19

Select the nearest answer

b)

obtained gain = \frac{V_0}{V_{in}} = 1 + \frac{36}{2} = 19

Expected gain = \frac{V_0}{V_{in}} = 20

∴ error = |\frac{19 - 20}{20}| × 100

            = 1/20 × 100            

            = 5%

6 0
3 years ago
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