A chemist dissolves 484 .mg of pure perchloric acid in enough water to make up 240.mL of solution. Calculate the pH of the solut
1 answer:
You might be interested in
Answer:
<em>The amount of Cl2 gas left , after the reaction goes to completion is : </em><u><em>139.655 grams</em></u>
Explanation:
Molar mass : It is the mass in grams present in one mole of the substance.
Moles of the substance is calculated by:
According to this equation:
2 mole of Al = 3 mole of Cl2 = 2 mole of AlCl3
Molar mass of Al = 27.0 g/mol
Mass of Al = 20.1 gram
Moles of Al present in the reaction :
Moles of Al = 0.744
Similarly calculate the moles of Cl2
Molar mass of Cl2 = 71.0 g/mol
Mass = 219 gram
Moles of Cl2 = 3.08 moles
According to equation,
2 mole of Al reacts with = 3 mole of Cl2
1 moles of Al reacts with = 3/2 mole of Cl2
0.744 moles of Al reacts with = 3/2(0.744) moles of Cl2
= 1.116 moles of Cl2
But actually present Cl2 = 3.08 moles
Hence Al is the limiting reagent , and Cl2 is the excess reagent.
The whole Aluminium Al get consumed during the reaction.
The amount of Cl2 in excess = Total Cl2 - Cl2 consumed
Cl2 in excess = 3.08 - 1.116 = 1.964 moles
<u>Cl2 in grams</u><u> </u>= 1.964 x 70.90 <u>= 139.655 grams</u>
Formation reaction is the formation of 1 mole of product from the constituents of the reactant molecules. The mass of oxygen that must react is 182 gm.
<h3>What is mass and molar mass?</h3>Mass of the substance is the weight while the molar mass of the substance is the addition of the atomic mass of the individual mass of the constituent atoms of the compound or the molecule.
The chemical reaction can be shown as:
From the reaction, it can be said that 3 moles of oxygen are required to produce 2 moles of aluminium oxide, so x moles of oxygen will be required to produce 3.80 moles of aluminium oxide.
Solving for x:
If 1 mol of oxygen is 32 gm then 5.7 moles of oxygen will be 182.4 gm.
Therefore, option D. 182 gm is the mass of oxygen required.
Learn more about moles and molar mass here: