Answer: A vacuum. Under the same conditions 16 s were required for the same number of moles of O2 to effuse. ... The molar mass of the unknown gas is 200 g/mol. calculation ... QUESTION 1 If gas-burning appliances are vented into an unlined masonry chimney, deteriorate and crumble and may · PLS HELP
Explanation:
Answer:
d = 9.5× 10⁻⁴ Kg/cm³
Explanation:
Given data:
Length of cube = 1.02 cm
Mass of cube = 0.001012 Kg
Density of cube = ?
Solution:
The length , height and width of cube is always same. Thus the volume of cube is,
Volume = length × height× width
Volume = 1.02 cm × 1.02 cm × 1.02 cm
Volume = 1.06 cm³
Density of cube:
d = 0.001012 Kg /1.06 cm³
d = 9.5× 10⁻⁴ Kg/cm³
Boyle's law gives the relationship between pressure and volume of gases.
it states that for a fixed amount of gas at constant temperature, pressure of gas is inversely proportional to volume.
PV = k
where P - pressure , V - volume and k - constant
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting this equation
P x 0.5650 L = 715.1 bar x 1.204 L
P = 1 524 bar
They produce a temporary surge of CO2 which is assimilated by flora and results in temp growth rate flux
Answer: 128 g/mol
Explanation:
Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.
Mathematically, that is:
Since, you know the ratio of two rates and the molar mass of one gas, you can calculate the molar mass of the other gas.
The molar mass of the oxygen molecule, O₂ = 2×16.0g/mol = 32.0 g/mol.
In the coming equations, I will use 32 g/mol for simplicity of writing.
So, the molecular mass of the unnknown gas is 128 g/mol.
