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kipiarov [429]
3 years ago
11

What is the chemical formila for monosaccharides?

Chemistry
1 answer:
Amanda [17]3 years ago
4 0
C6h12o6 is the chemical formila for monosaccarides
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A 4.86-gram sample of calcium reacted completely with oxygen to form 6.80 grams of calcium oxide. This reaction is represented b
sesenic [268]
The number of mole of Ca reacted is:
4.86 g Ca/ (40.08 g/mol Ca)= 0.121 mol Ca

Because Ca reacted completely with oxygen and there is 2 mol Ca, there is 1 mol O2 reacted.

Total mass of oxygen that reacted is:
0.121 mol Ca* (1mol O2/ 2 mol Ca)* (32 g O2/ 1 mol O2)= 1.94 g O2 reacted.

Hope this would help~
8 0
3 years ago
What is different between margerine and butter in term of organic chemistry
Brut [27]

Answer:

The most important difference between the two is that butter is derived from dairy and is rich in saturated fats, whereas margarine is made from plant oils. ... If the margarine contains partially hydrogenated oils, it will contain trans fat, even if the label claims that it has 0 g.

Explanation:

(⌒_⌒;)

4 0
3 years ago
At what year will Sagittarius be visible from the earth’s North Pole?
jek_recluse [69]
Best visible at 9.pm during the month of August. (Sagittarius is best observed during the Northern hemisphere summer months) .. I hope this helped ?
8 0
2 years ago
Will mark the brainiest later for correct answers! Please show work.
Elodia [21]

Answer:

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles and weighs equal to its molecular mass.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles}=\frac{\text{Given molecules}}{\text {Avogadros number}}

a. moles in 14.08 g of C_{12}H_{22}O_{11} = \frac{14.08g}{342.3g/mol}=0.04113moles

molecules in 14.08 g of C_{12}H_{22}O_{11} = 0.04113\times 6.023\times 10^{23}=0.2477\times 10^{23}

b. moles in 17.75 g of NaCl = \frac{17.75g}{58.5g/mol}=0.3034moles

molecules in 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

formula units 17.75 g of NaCl = 0.3034\times 6.023\times 10^{23}=1.827\times 10^{23}

c. moles in 20.06 g of  CuSO_4.5H_2O= \frac{20.06g}{249.68g/mol}=0.08034moles

formula units in 20.06 g of  CuSO_4.5H_2O= 0.08034\times 6.023\times 10^{23}=0.4839\times 10^{23}

7 0
3 years ago
Hi! please help me identify the IUPAC name for the structures ​
Snowcat [4.5K]

The IUPAC names of the organic compounds would be as follows:

1. Methanol or 1-Methanol

2. Propan-2-ol or 2-Propanol

3. 2-MethylButane

4. 1-Hexanol

5. 1-Heptanol

<h3>Naming organic compounds</h3>

In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:

  • The longest carbon chain, otherwise known as the parent chain, is considered.
  • The substituents must be identified
  • The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
  • Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.

Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:

  • Methanol or 1-Methanol
  • Propan-2-ol or 2-Propanol
  • 2-MethylButane
  • 1-Hexanol
  • 1-Heptanol

More on IUPAC naming can be found here: brainly.com/question/16631447

#SPJ1

7 0
1 year ago
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