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Eddi Din [679]
3 years ago
8

What is the direction of force of friction acting ona moving objec

Physics
1 answer:
PIT_PIT [208]3 years ago
4 0
The direction of the friction force is the same than the movement, but its sense is the opposite.
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A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. How far away is the reflecting object? (c
Assoli18 [71]

A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. The reflecting object would be 3000 m away .

Phenomenon of hearing back our own sound is called an echo. It is due to successive reflection of sound waves from the surfaces or obstacles of large size. To hear an echo, there must be a time gap of 0.1 second in original sound and the reflected sound.

Given

time =  20 μs = 20 * 10^{-6} s

let distance to the reflecting surface be = x

total distance travelled by pulse will be  = 2x

speed = 3.0 × 10^{8} m/s

distance = speed * time

2x = 3.0 × 10^{8} * 20 * 10^{-6}

   x = 3000 m

The reflecting object would be 3000 m away

To learn more about echo here

brainly.com/question/14861578?referrer=searchResults

#SPJ4

5 0
2 years ago
describe the relationship between the direction of the velocity vector and the direction of the acceleration for a body moving i
Xelga [282]

Answer:

a = v²/r

Explanation:

The acceleration of a body moving in a circular path is known as the centripetal acceleration. This is the acceleration of a body that keeps the body within the circular path. It is written in terms of the linear velocity v and the radius of the circle of rotation as shown;

a = v²/r where

v is the linear velocity

r is the radius

a is the centripetal acceleration

7 0
3 years ago
D
anastassius [24]

Answer:

the answer is c

Explanation:

7 0
3 years ago
A long string is pulled so that the tension in it increases by a factor of four. If the change in length is negligible, by what
rusak2 [61]

To solve this problem we will apply the concepts related to wave velocity as a function of the tension and linear mass density. This is

v = \sqrt{\frac{T}{\mu}}

Here

v = Wave speed

T = Tension

\mu = Linear mass density

From this proportion we can realize that the speed of the wave is directly proportional to the square of the tension

v \propto \sqrt{T}

Therefore, if there is an increase in tension of 4, the velocity will increase the square root of that proportion

v \propto \sqrt{4} = 2  

The factor that the wave speed change is 2.

3 0
3 years ago
What is the value of acceleration due to gravity, g, on Earth?
qwelly [4]

Explanation:

It varies with altitude, but at sea level, it's 9.8 m/s².

8 0
4 years ago
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