Question

if a gas has a volume of 2.60 L at a pressure of 1.60atm, what will its new volume be at a pressure of 10.6 atm

Answer 1

Answer:

0.39L

Explanation:

Given parameters:

Initial volume of gas V₁ = 2.6L

Initial pressure on gas P₁ = 1.6atm

Final volume of gas V₂ = ?

Final pressure on gas P₂ = 10.6atm

Solution

Applying Boyle's law which states that "the volume of a fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

                      P₁V₁ = P₂V₂

                      V₂ = $\frac{P_{1}V_{1} }{P_{2} }$

                      V₂ =  $\frac{1.6 x 2.6 }{10.6 }$ = 0.39L