Answer:
t = 2.38 [s]
Explanation:
To solve this problem we must use the following equation of kinematics. We must clarify that both the acceleration and the initial velocity were taken as positive, since the velocity of the movement coincides with the direction of the acceleration.
where:
x - Xo = distance = 47 [m]
Vo = initial velocity = 8 [m/s]
a = gravity acceleration = 9.81 [m/s²]
t = time [s]
Now replacing these values in the equation:
47 = 8*t + 0.5*9.81*t²
47 = 8t + 4.905t²
47 = 4.905*t(1.63 + t)
9.58 = t*(1.63 + t) solving this equation (cuadratic)
we found that t = 2.38 [s]
Answer:
At the maximum height the ball will have an instantaneous velocity of zero. The formula for instantaneous velocity is
v = v₀ + at
Where v is the instantaneous velocity, v₀ is the initial velocity, a is the acceleration due to gravity, -9.8 m/sec², and t is the time.
We need instantaneous velocity to = 0.
0 = 20 - 9.8t : Isolate t => 1st step: Add 9.8t to both sides
9.8t = 20 : Isolate t => 2nd step: Divide both sides by 9.8
t = 2.04 seconds (approximately)
Explanation:
Answer:
2.21 N
Explanation:
The force in this case is the total mass multiplied by the acceleration due to gravity. You are not asked for the solution to be in terms of the torque which is the usual way to solve these problems. That's why you are not given where the fulcrum is.
The fulcrum feels F1 + F2 + 34 * 980
F2 = 141.7 * 980 = 138866
F1 = 50.3 * 980 = 49294
Ruler = 34 * 980= 33320
Total Force = 221480 The units here are dynes
I just saw in the middle of the question that g = 9.80
So the answer becomes 221480 / 1000 = 221.48 because we needed kg
And that answer becomes 221.48/100 2.21 because the force of gravity should be 9.8 not 980
The total force exerted on the fulcrum is