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defon
2 years ago
3

A radio operating at 3.0 volts and a constant

Physics
1 answer:
sveta [45]2 years ago
3 0
We can do this using V=IR

Substituting values in we get 3 = (1.8x10^-4) x R
R=3/0.00018
R=16666 = 17000 to 2sf

Therefore, the resistance of the radio circuit is 1.7x10^4 Ohms
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A car going 50 mph accelerates to pass a truck. Five seconds later the car is
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The vehicle accelerates at 2.648 m/s².

We have:

Initial velocity, u = 50 miles per hour = 22.352 m/s

final velocity, v = 80 miles per hour = 35.762 m/s

Time, t = 5 seconds

The time in hours is:

t = 5 seconds

Now, the acceleration of the car can be calculated using the formula:

v = u + at

35.762 = 22.352 + a(5)

a(5) = 30

a = 2.682 m/s²

From the calculations above, the acceleration of the car is 2.682 m/s².

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2 years ago
A man stands still on a moving walkway and a woman walks past him in the
mixer [17]

Answer:

The woman is walking at a speed of 0.08 m/s relative to the man on the walkway.

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those 0.38 m/s reported from a stationary observer are in fact the addition of two velocities: that of the walkway (0.3 m/s), and that of the woman relative to the walkway (our unknown velocity "v"):

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