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mixer [17]
3 years ago
6

Karen drops a 2.0 kg rock from the top of a mountain. Determine the distance the rock travels after falling for 3 seconds assumi

ng it has reached free fall and given the gravitational acceleration of 9.8 m/sec2 downward. [HINT: Distance=(0.5)*(acceleration)*(time2)]
Physics
2 answers:
aev [14]3 years ago
8 0
Um...Is it 29.4m? I'm guessing, since, there's 3 seconds and it's at 9.8m/sec downward, so,

9.8 x 3 = 29.4m
Artemon [7]3 years ago
8 0

Explanation:

The data given is as follows.

     mass = 2.0 kg

     time = 3 seconds

 gravitational acceleration = 9.8 m/s^{2}

Calculate the distance traveled by the rock when it falls is as follows.

          Distance = \frac{1}{2} \times acceleration \times time^{2}

                                 = \frac{1}{2} \times 9.8 m/s^{2} \times (3 second)^{2}

                                 = \frac{1}{2} \times 9.8 m/s^{2} \times 9 second^{2}

                                 = 44.1 m

Therefore, the distance traveled by rock is 44.1 meter.

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