Calculate the line parameters ????′, ????′, ????′, and ????′ for a coaxial line with an inner conductor diameter of 0.5 cm and a
n outer conductor diameter of 1 cm, filled with an insulating material where ???? = ????0, ???????? = 4.5, and ???? = 10−3 ????⁄m. The conductors are made of copper with ????c = ????0 and ????c = 5.8 × 107 ????⁄m. The operating frequency is 1 ????Hz.
(a) Calculate the line parameters at 1 GHz.
(b) Compare your results with those based on CD Module 2.2 Include a printout of the screen display.
(a) Calculate the line parameters at 1 GHz.
(b) Compare your results with those based on CD Module 2.2 Include a printout of the screen display.
1 answer:
You might be interested in
Answer:
Check the explanation
Explanation:
to know the lift per unit span (N/m) that is expected to be measured when the wing attack angle is 4°
as well as the corresponding section lift coefficient and die moment coefficient .
Kindly check the attached image below to see the step by step explanation to the above question.
Answer:
5.6 mm
Explanation:
Given that:
A cylindrical tank is required to contain a:
Gage Pressure P = 560 kPa
Allowable normal stress = 150 MPa = 150000 Kpa.
The inner diameter of the tank = 3 m
In a closed cylinder there exist both the circumferential stress and the longitudinal stress.
Circumferential stress
Making thickness t the subject; we have
t = 0.0056 m
t = 5.6 mm
For longitudinal stress.
t = 0.0028 mm
t = 2.8 mm
From the above circumferential stress and longitudinal stress; the stress with the higher value will be considered ; which is circumferential stress and it's minimum value with the maximum thickness = 5.6 mm
Answer:
Velocity of ball B after impact is and ball A is
Explanation:
= Initial velocity of ball A
= Initial velocity of ball B = 0
= Final velocity of ball A
= Final velocity of ball B
= Coefficient of restitution = 0.8
From the conservation of momentum along the normal we have
Coefficient of restitution is given by
Adding the above two equations we get
From the conservation of momentum along the plane of contact we have
Velocity of ball B after impact is and ball A is
.