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larisa86 [58]
3 years ago
12

To fine the number of neutrons in an atom, subtract its_____

Chemistry
1 answer:
storchak [24]3 years ago
3 0

a is the answer hope this helps

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Removing seed casings from grains is SEPARATING. a soda bubble bubbling when it is opened is MIXING. a bright copper statue turning green is MIXING. remove salt from seawater is SEPARATING. water decomposing is SEPARATING.
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Pls help! I'll give u 10 points and the brainlest answer!!!​
alekssr [168]

Answer:

371km

Explanation:

the lower the more fuel there is

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Which nitrogen-containing base is found only in rna?
bija089 [108]
The answer to this is Codon. 
3 0
3 years ago
Cobalt-63 has a half-life of 5.3 years. If a pellet that has been in storage for 15.9 years contains 40.0g of Cobalt-63, how muc
Cerrena [4.2K]

Answer:

320 g  

Step-by-step explanation:

The half-life of Co-63 (5.3 yr) is the time it takes for half of it to decay.  

After one half-life, half (50 %) of the original amount will remain.  

After a second half-life, half of that amount (25 %) will remain, and so on.  

We can construct a table as follows:  

  No. of               Fraction         Mass

half-lives   t/yr   Remaining   Remaining/g

      0        0              1

      1         5.3           ½

     2        10.6           ¼

     3        15.9           ⅛                 40.0

     4        21.2           ¹/₁₆

We see that 40.0 g remain after three half-lives.

This is one-eighth of the original mass.

The mass of the original sample was 8 × 40 g = 320 g

5 0
3 years ago
A home solar energy storage unit uses 4.75 ✕ 102 L of water for storing energy. On a sunny day, the water absorbed 2.75 ✕ 104 kJ
Sav [38]

Answer : The water's temperature change will be, 13.85^oC

Explanation : Given,

Density of water = 0.998 g/mL

Volume of water = 4.75\times 10^2L=4.75\times 10^5mL

(conversion used : 1 L = 1000 mL)

Specific heat of water = 4.184J/g^oC

Heat absorbed = 2.75\times 10^4kJ=2.75\times 10^7J

(conversion used : 1 kJ = 1000 J)

First we have to determine the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.998g/mL)\times (4.75\times 10^5mL)=474050g

Now we have to calculate the change in temperature of water.

Formula used :

Q=m\times C_w\times \Delta T

where,

Q = heat absorbed by water

m = mass of water

C_w = specific heat of water

\Delta T = change in temperature

Now put all the given value in the above formula, we get:

2.75\times 10^7J=474050g\times 4.184J/g^oC\times \Delta T

\Delta T=13.85^oC

Therefore, the water's temperature change will be, 13.85^oC

8 0
3 years ago
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