Question

Consider a single crystal of silver oriented such that a tensile stress is applied along a [001] direction. If slip occurs on a (111) plane and in a [1¯01] direction, and is initiated at an applied tensile stress of 1.1 MPa (160 psi), compute the critical resolved shear stress.

Answer 1

Answer:

The answer is 0.4490Mpa

Explanation:

Given :

P in direction of 001 , P = 1.1MPa

slip   plane  =  111, slip plane normal direction of 111,

slip direction = 101

$T_{R}$ = δcosФcosλ

= (001 * 101) = 1 = $\sqrt{2}$cosλ

(111 * 001) 1 $\sqrt{3}$cosФ

= 1.1 MPa * $\frac{1}{\sqrt{2} }$ * $\frac{1}{\sqrt{3} }$

1.1 Mpa * 1/1.4142 * 1/1.7320

1.1 Mpa * 0.7072 * 0.5773

= 0.4490 MPa

therefore the resolved shear stress = 0.4490MPa