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Aleks [24]
2 years ago
13

What would happen if water could not condense in the atmosphere

Physics
2 answers:
Harrizon [31]2 years ago
7 0
-- As more water evaporated from lakes, rivers, ponds, and people, the
water vapor in the atmosphere would build up and build up and build up,
until the atmosphere could not hold any more water vapor. 

-- The water would stay there in the atmosphere.  There would never be
any more rain, sleet, hail, fog, drizzle, mist, or snow.

-- Rivers flow out of lakes and ponds, carrying lake water to the sea. 
Rain keeps the lakes refilled. 
   The lakes would eventually dry out as the rivers drained them, and then
the rivers would run dry.  It would be the end of trees, forests, and farming.

-- At the instant when the atmosphere became full of all the water vapor
it could hold, all evaporation on Earth would stop. 

. . . . . When you washed the dishes, you could leave them standing in the
drainer rack for a week, but they would never dry.

. . . . . You could hang up your bath towel and the laundry in your room or
in the back yard, but it would never dry.

. . . . . When you boiled a pot of water on the stove, I'm not sure exactly
what would happen, but I know that the steam could not just rise from
the pot and disappear.  The atmosphere couldn't absorb it, so I guess
it would be this dense cloud of boiling hot fog that would rise from the pot
and fill the kitchen.  If you walked through it, it would swirl and drift around.
Eventually it would settle on the walls, and when the droplets got big enough,
they would run down the walls and make puddles on the floor.

. . . . . It would be pretty bad for people and animals.  We generate a lot of heat
inside our bodies, and we get rid of the heat by perspiring.  Moisture comes
out of our skin and evaporates into the air, which takes heat with it. 
   If the atmosphere was full with as much water vapor as it could hold, then
perspiration could not evaporate.  We would ALWAYS be walking around
in 100% humidity, with water running off of our skin onto the floor.  The only
way we could cool ourselves would be to pour cold water on ourselves. 
Anybody who didn't do that every couple of minutes would pass out from
heat exhaustion, as his inside temperature got too high.

Our dogs don't even perspire.  The only way they can get rid of heat is to
make their tongues wet and then blow air over it.  That's why when they
run, or when the weather is hot, they drink a lot and pant fast.  The water
evaporating from their tongues is the only way they can get rid of heat. 
If the atmosphere could not take any evaporation, then our dogs would
probably stop moving around at all, and just lay around all day, drinking
cold water.

In short, I think it's accurate to say that if condensation of water in the
atmosphere stopped, then evaporation would stop, and it would only be
a matter of time before life on Earth stopped. 
Umnica [9.8K]2 years ago
5 0
It will happen to cause that the water will be returned back and it will not be evaporated, etc, look into the carbon cycle or water cycle for your answer
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Active transport move molecules from low concentrations to high concentrations.
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Examine the images of the Grand Canyon below. Notice that most of the canyon consists of layers of sedimentary rocks, but if you
Tomtit [17]

Intense temperature and pressure of regional metamorphism

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3 years ago
The transverse standing wave on a string fixed at both ends is vibrating at its fundamental frequency of 250 Hz. What would be t
hodyreva [135]

Answer:

Explanation:

fundamental frequency, f = 250 Hz

Let T be the tension in the string and length of the string is l ans m be the mass of the string initially.

the formula for the frequency is given by

f=\frac{1}{2l}\sqrt{\frac{Tl}{m}}    .... (1)

Now the length is doubled ans the tension is four times but the mass remains same.

let the frequency is f'

f'=\frac{1}{2\times 2l}\sqrt{\frac{4T\times 2l}{m}}    .... (2)

Divide equation (2) by equation (1)

f' = √2 x f

f' = 1.414 x 250

f' = 353.5 Hz

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3 years ago
The number of flowers on different breeds of bushes in a greenhouse is recorded every week for two months.
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Is there a equation or something so I can do the math of how many flowers there are at the end of the two monthsm

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2 years ago
A point charge (–5.0 µC) is placed on the x axis at x = 4.0 cm, and a second charge (+5.0 µC) is placed on the x axis at x = –4.
AveGali [126]

Answer:

The magnitude of electric force is  7.2\times10^{-3} N

Explanation:

Coulomb's Law:

The force of attraction or repletion is

  • directly proportional to the products of charges i.e F\propto q_1q_2
  • inversely proportional to the square of distance i.e F\propto \frac{1}{r^2}

\therefore F\propto \frac{q_1q_2}{r^2}

\Rightarrow F=k \frac{q_1q_2}{r^2}    [ k is proportional constant=9×10⁹N m²/C²]

There are two types of force applied on Q=+2.5 μC=2.5×10⁻⁶ C

Let F₁ force be applied on Q =+2.5 μC by q₁= -5.0 μC = - 5.0×10⁻⁶ C

and F₂ force  be applied on Q=+2.5 μC by q₂= 5.0 μC= 5.0×10⁻⁶ C

Since the magnitude of F₁ and F₂ are same. Therefore their y component cancel.

If we draw a line from q₁ to Q .

The it forms a triangle whose base = 4.0 cm and altitude =3.0 cm.

Let hypotenuse = r

Therefore, r=\sqrt{altitude^2+base^2} =\sqrt{3^2+4^2} =5

we know,

cos \theta = \frac{base }{hypotenuse}

\Rightarrow cos \theta = \frac{4 }{r}

Total force F_Q = 2.F_1 cos\theta \hat{i}

                         =2k\frac{Qq_1}{r^2} cos\theta \hat i

                         =2\ \frac{9\times1 0^9\times2.5 \times 5\times 10^{-12}}{r^2} \frac{4}{r} \hat i

                         =8\ \frac{9\times10^9\times2.5 \times 5\times 10^{-12}}{5^3} \hat i     [ r=5]

                         =7.2\times10^{-3}\hat i   N

The magnitude of electric force is  7.2\times10^{-3} N

                         

3 0
3 years ago
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