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Aleks [24]
3 years ago
13

What would happen if water could not condense in the atmosphere

Physics
2 answers:
Harrizon [31]3 years ago
7 0
-- As more water evaporated from lakes, rivers, ponds, and people, the
water vapor in the atmosphere would build up and build up and build up,
until the atmosphere could not hold any more water vapor. 

-- The water would stay there in the atmosphere.  There would never be
any more rain, sleet, hail, fog, drizzle, mist, or snow.

-- Rivers flow out of lakes and ponds, carrying lake water to the sea. 
Rain keeps the lakes refilled. 
   The lakes would eventually dry out as the rivers drained them, and then
the rivers would run dry.  It would be the end of trees, forests, and farming.

-- At the instant when the atmosphere became full of all the water vapor
it could hold, all evaporation on Earth would stop. 

. . . . . When you washed the dishes, you could leave them standing in the
drainer rack for a week, but they would never dry.

. . . . . You could hang up your bath towel and the laundry in your room or
in the back yard, but it would never dry.

. . . . . When you boiled a pot of water on the stove, I'm not sure exactly
what would happen, but I know that the steam could not just rise from
the pot and disappear.  The atmosphere couldn't absorb it, so I guess
it would be this dense cloud of boiling hot fog that would rise from the pot
and fill the kitchen.  If you walked through it, it would swirl and drift around.
Eventually it would settle on the walls, and when the droplets got big enough,
they would run down the walls and make puddles on the floor.

. . . . . It would be pretty bad for people and animals.  We generate a lot of heat
inside our bodies, and we get rid of the heat by perspiring.  Moisture comes
out of our skin and evaporates into the air, which takes heat with it. 
   If the atmosphere was full with as much water vapor as it could hold, then
perspiration could not evaporate.  We would ALWAYS be walking around
in 100% humidity, with water running off of our skin onto the floor.  The only
way we could cool ourselves would be to pour cold water on ourselves. 
Anybody who didn't do that every couple of minutes would pass out from
heat exhaustion, as his inside temperature got too high.

Our dogs don't even perspire.  The only way they can get rid of heat is to
make their tongues wet and then blow air over it.  That's why when they
run, or when the weather is hot, they drink a lot and pant fast.  The water
evaporating from their tongues is the only way they can get rid of heat. 
If the atmosphere could not take any evaporation, then our dogs would
probably stop moving around at all, and just lay around all day, drinking
cold water.

In short, I think it's accurate to say that if condensation of water in the
atmosphere stopped, then evaporation would stop, and it would only be
a matter of time before life on Earth stopped. 
Umnica [9.8K]3 years ago
5 0
It will happen to cause that the water will be returned back and it will not be evaporated, etc, look into the carbon cycle or water cycle for your answer
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A 35 kg boy is riding a 65 kg go-cart. He pushes on the gas pedal, causing the cart to accelerate at 5 m/s2. Use the equation F
trasher [3.6K]

Answer:

\boxed {\boxed {\sf 500 \ Newtons }}

Explanation:

The equation for force is given:

F=m*a

First, we must find the total mass, which is the sum of the boy's mass and the go-cart's mass.

  • total mass= boy's mass + go cart's mass

The boy's mass is 35 kilograms and the go cart's is 65 kilograms.

  • total mass= 35 kg+ 65 kg=100 kg

Now we know the total mass and the acceleration.

m= 100 \ kg \\a= 5 \ m/s^2

Substitute the values into the formula.

F=100 \ kg * 5 \ m/s^2

Multiply.

F= 500 \ kg*m/s^2

  • 1 kilograms meter per square second is equal to 1 Newton.
  • Our answer of 500 kg*m/s² is equal to 500 Newtons.

F= 500 \ N

The force exerted by the go cart engine is <u>500 Newtons.</u>

4 0
3 years ago
Read 2 more answers
You have a rock sample and analyze it for the presence of radioactive isotopes in order to determine when it was formed. You fin
Firdavs [7]

Answer:

the decay of half of the nuclei only a half-life has passed ,  b) in rock time it is 1 108 years

Explanation:

The radioactive decay is given by

         N = N₀ e^{\lambda t}

If half of the atoms have decayed

       ½ N₀ = N₀ e^{\lambda t}

       ½ = e^{\lambda t} ₀

       Ln 0.5 = - λ t

       t = - ln 0.5 /λ

The definition of average life time is

      T_{1/2}= ln 2 / λ

       λ = ln 2 /  T_{1/2}

       λ = 0.693 / 100 10⁶

       λ = 0.693 10⁻⁸ years

We replace

       t = -ln 0.5 / 0.693 10⁻⁸

       t = 10⁸ years

We see that for the decay of half of the nuclei only a half-life has passed

b) in rock time it is 1 108 years

8 0
3 years ago
The brakes application to a car produce an acceleration of 6ms2 in the opposite direction to the motion .If the car takes 2 seco
Anna [14]

Answer:12 meter

Explanation:

acceleration(a)=6m/s^2

Time(t)=2 seconds

Distance =(a x t^2)/2

Distance =(6 x 2^2)/2

Distance=(6 x 2 x 2)/2

Distance=24/2

Distance =12

Distance is 12 meters

7 0
3 years ago
When you put a pot of water on the stove, the stove transfers thermal energy to the water. As the water gains large
STALIN [3.7K]

Answer:

It releases some of the energy into the atmosphere as hot steam.

Explanation:

8 0
3 years ago
g a small smetal sphere, carrying a net charge is held stationarry. what is the speed are 0.4 m apart
Veseljchak [2.6K]

Answer:

The speed of q₂ is 4\sqrt{10}\ m/s

Explanation:

Given that,

Distance = 0.4 m apart

Suppose, A small metal sphere, carrying a net charge q₁ = −2μC, is held in a stationary position by insulating supports. A second small metal sphere, with a net charge of q₂ = −8μC and mass 1.50g, is projected toward q₁. When the two spheres are 0.800m apart, q₂ is moving toward q₁ with speed 20m/s.

We need to calculate the speed of q₂

Using conservation of energy

E_{i}=E_{f}

\dfrac{1}{2}mv_{i}^2+\dfrac{kq_{1}q_{2}}{r_{i}}=\dfrac{kq_{1}q_{2}}{r_{f}}+\dfrac{1}{2}mv_{f}^2

\dfrac{1}{2}m(v_{i}^2-v_{f}^2)=kq_{1}q_{2}(\dfrac{1}{r_{f}}-\dfrac{1}{r_{i}})

Put the value into the formula

\dfrac{1}{2}\times1.5\times10^{-3}(20^2-v_{f}^2)=9\times10^{9}\times-2\times10^{-6}\times-8\times10^{-6}(\dfrac{1}{(0.4)}-\dfrac{1}{(0.8)})

0.00075(400-v_{f}^2)=0.18&#10;

400-v_{f}^2=\dfrac{0.18}{0.00075}

-v_{f}^2=240-400

v_{f}^2=160

v_{f}=4\sqrt{10}\ m/s

Hence, The speed of q₂ is 4\sqrt{10}\ m/s

7 0
3 years ago
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