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natka813 [3]
3 years ago
8

A raccoon falls out of a tree from a height of 1.2. Which equation can you use to calculate the time it takes for the raccoon to

fall to the ground?
Physics
1 answer:
Inga [223]3 years ago
3 0

Answer:

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2 \cdot 1.2 m}{9.81 m/s^2}}=0.50 s

Explanation:

The equation that we can use to calculate the time it takes for the raccoon to fall to the ground is:

t=\frac{2S}{g}

where S=1.2 m is the height of the tree and g=9.81 m/s^2 is the acceleration due to gravity. This equation is derived from the equation of the distance in a uniformly accelerated motion, which is given by

S=S_0 + v_0 t + \frac{1}{2}at^2

where S0 is the initial position, v0 is the initial velocity and t the time. In this problem, we can put S0=0 (we can take the initial position as the initial position of the raccoon) and v0=0 (the raccoon starts from rest), so the equation becomes

S=\frac{1}{2}at^2

and since the motion is a free fall, the acceleration is equal to the acceleration of gravity, so a=g:

S=\frac{1}{2}gt^2

And by re-arranging it, we find

t=\sqrt{\frac{2S}{g}}

By substituting numbers, we find

t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2 \cdot 1.2 m}{9.81 m/s^2}}=0.50 s

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Caribbean:
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2 years ago
An air-plane has an effective wing surface area of 17.0 m² that is generating the lift force. In level flight the air speed over
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Answer:

Explanation:

Given that,

Surface area A= 17m²

The speed at the top v" = 66m/s

Speed beneath is v' =40 m/s

The density of air p =1.29kg/m³

Weight of plane?

Assuming that,

the height difference between the top and bottom of the wind is negligible and we can ignore any change in gravitational potential energy of the fluid.

Using Bernoulli equation

P'+ ½pv'²+ pgh' = P'' + ½pv''² + pgh''

Where

P' is pressure at the bottom in N/m²

P" is pressure at the top in N/m²

v' is velocity at the bottom in m/s

v" is velocity at the top in m/s

Then, Bernoulli equation becomes

P'+ ½pv'² = P'' + ½pv''²

Rearranging

P' — P'' = ½pv"² —½pv'²

P'—P" = ½p ( v"² —v'²)

P'—P" = ½ × 1.29 × (66²-40²)

P'—P" = 1777.62 N/m²

Lift force can be found from

Pressure = force/Area

Force = ∆P ×A

Force = (P' —P")×A

Since we already have (P'—P")

Then, F=W = (P' —P")×A

W = 1777.62 × 17

W = 30,219.54 N

The weight of the plane is 30.22 KN

5 0
3 years ago
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Suppose that a simple pendulum consists of a small 60.0 g bob at the end of a cord of negligible mass. If the angle 0 between th
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Based on the mass of the bob and the angle between the cord and the vertical, the pendulum length is 0.50m.

The maximum kinetic energy can be found to be 9.42 x 10⁻⁴J.

<h3>What is the pendulum length?</h3>

This can be found as:

= g-force / w²

Solving gives:

= 9.8 / 4.43²

= 0.4998 m

= 0.50 m

<h3>What is the maximum kinetic energy?</h3>

This can be found as:

= 0.5 × m × w² × A²

Maximum kinetic energy is:

= 0.5 × 60 × 10⁻³ × (4.43 × 0.4998 x 0.08 rad)²

= 9.42 x 10⁻⁴J

Find out more on maximum kinetic energy at brainly.com/question/24690095.

5 0
1 year ago
A passenger on a stopped bus notices that rain is falling vertically just outside the window. When the bus moves with constant v
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Answer:

1)0.325

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Explanation:

<u>Given:</u>

The angle that falling raindrops make with the vertical=18^\circ

Let V_R be the velocity of the raindrops and V_B be the velocity of the bus.

1)

\dfrac{V_R}{V_B}=\tan 18^\circ\\\dfrac{V_R}{V_B}=0.315\\

2)Speed of the raindrops=0.315\times 19

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Answer:

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Explanation:

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Range R = U√2H/g

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g is the acc due to gravity = 9.8m/s²

R = 3.5m

Substitute into the formula and get H

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square both sides

0.7292² = 2H/9.8

2H = 0.7292² * 9.8

2H = 5.21

H = 5.21/2

H = 2.605m

Hence the height of the ball from the ground is 2.605m

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