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VladimirAG [237]
3 years ago
10

What is the binding energy (in MeV per nucleon) for the ⁶₃Li nucleus?

Physics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

Explanation:

⁶₃Li will have 3 protons and 3 neutrons .

mass of proton in amu = 1.00727 amu

mass of neutron in amu = 1.00866 amu

mass of lithium nucleus in amu = 6.01512 amu

mass defect = 3 (  1.00727  + 1.00866 ) - 6.01512 amu

= .03267 amu

Binding energy = mass defect in amu x 931 Mev

= 30.41 MeV

binding energy per nucleon

no of nucleon = 3 + 3 = 6

binding energy per nucleon = 30.41 / 6 Mev

= 5.068 MeV .

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In the given figure below we have

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2 years ago
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emmasim [6.3K]
<h2>Answer:</h2>

<u>Distance covered is 6.9 meters</u>


<h2>Explanation:</h2>

Data given:

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4 0
3 years ago
Read 2 more answers
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