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DiKsa [7]
3 years ago
7

A force that keeps an object at a fixed angle

Physics
1 answer:
Helga [31]3 years ago
3 0
I'm pretty sure it's called, "gravity". or gravy :) 
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In your own words, explain what conservation of energy means. Also, give an example of the conservation of energy using somethin
Genrish500 [490]
Energy can not be created or destroyed but can change from one form to another.

example: as a roller coaster cart loses height the more speed it gains, the potential energy is transferred into kenetic energy
8 0
3 years ago
Eric drops a 2.20 kg water balloon that falls a distance of 45.08 m off the top of a
Marianna [84]

Answer:

972 J

Explanation:

At the bottom, all the gravitational potential energy was converted into kinetic energy. If you calculate the GPE, its value will be the same that the KE at the bottom. The GPE can be calculated this way:

GPE = mass×gravity×heigth

GPE = 2.2×9.8×45.08 ≈ 972

4 0
2 years ago
To avoid an accident, a driver steps on the brakes to stop a 1000kg car traveling at 65km/h. If the braking distance is 35m, how
Alenkinab [10]
To stop the car it would be 100m because if the car is going to 65km/h then it would still be 100km/h
8 0
3 years ago
PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works
steposvetlana [31]

Solved your another question same like this with scaling to Cm this time we go with metre(m)

Scale factor

  • 1km=10³m
  • 1m=10^{-3}km

Mercury

  • 58000m

Ven us

  • 108000m

Earth

  • 150000m

Mars

  • 228000m

Jupiter

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Saturn

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7 0
2 years ago
A milliammeter has an internal resistance of 5ohms and
Vikentia [17]

Answer:

Rs = 0.02008 Ω = 20.08 mΩ

Explanation:

The range of an ammeter can be increased by connecting a small shunt resistance to it in a series combination. This shunt resistance can be calculated by the following formula:

Rs = \frac{I_gR_g}{I - I_g}

where,

R_s = value of shunt resistance = ?

I_g = current range of ammeter = 20 mA = 0.02 A

I = Required range of ammeter = 5 A

R_g = Resistance of ammeter = 5 ohms

Therefore,

R_s = \frac{(0.02\ A)(5\ ohms)}{5\ A-0.02\ A}

<u>Rs = 0.02008 Ω = 20.08 mΩ</u>

7 0
3 years ago
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