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Viefleur [7K]
3 years ago
5

When 2 grams of hydrogen (h2) react with 32 grams of oxygen (O2) the reaction yields hydrogen peroxide (h2o2) how many grams of

ho202 are produced in this reaction
Physics
1 answer:
MissTica3 years ago
6 0

as per the reaction we have

H_2 + O_2 ---> H_2O_2

so here 1 mole of H2 react with 1 mole of O2 and give 1 mole of H2O2 as the product

now we will find the moles of given reactant

moles of H2

n_1 = \frac{2}{2} = 1 mole

moles of O2

n_2 = \frac{32}{32} = 1 mole

so here both present in 1 mole each hence the product will also formed 1 mole

so here we have

n = 1 mole H2O2 will form

so mass of the product

mass = moles* molecular mass

m = 1 * (2 + 32)

m = 34 g

so the product mass will be 34 g

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When studying atoms, scientists can ignore the ______ force between charged particles that make up the atoms because it is many
MArishka [77]

Answer:

Gravitational

Explanation:

When studying atoms, scientists can ignore the  gravitational force between charged particles that make up the atoms because it is many millions of times smaller than other forces in the atom.

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3 years ago
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A football field lies so one endzone is to the east and one is to the west. A running back gets the ball and starts running 20o
Jobisdone [24]

Answer:

( 80.87 i - 12.96 j ) m

Explanation:

Running back movements :

20⁰ north of east  for  10 meters,  

Runs straight east for 60 meters

runs 35⁰ east of south for 20 meters

A) show vector pointing from the starting point to the end ( where he scored )

The final vector displacement : ( 80.87 i - 12.96 j ) m

which is : 81.90 m, 9.10⁰ south of east

attached below is the required  diagram

8 0
3 years ago
(answer the question or get reported) Please solve it with the steps thanks :)​
DaniilM [7]

Answer:

Fx = 35.36 N

Fy = 35.36 N

Explanation:

From the question,

The X component of the force is

Fx = Fcos∅.................. Equation 1

Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.

Give: F = 50 N, ∅ = 45°

Substitute into equation 1

Fx = 50(cos45°)

Fx = 50(0.7071)

Fx = 35.36 N

Similarly,

For Y component

Fy = Fsin∅

Where F y = Y component

Fy = 50(sin45°)

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4 0
2 years ago
State coulomb's law mathematically
Vsevolod [243]

Coulomb's law is express as:

\begin{gathered} F=k\frac{q_1q_2}{r^2} \\ \text{ where} \\ k\text{ is Coulomb's constant} \\ q_1\text{ and }q_2\text{ are the charges} \\ r\text{ is the distance between charges} \end{gathered}

7 0
1 year ago
Una rueda que tiene 15 cm de radio, realiza 64 vueltas en 16 seg. Calcula: Periodo Frecuencia Velocidad angular Velocidad lineal
liraira [26]

Answer:

i) El período de la rueda es de 0,25 segundos.

ii) La frecuencia de la rueda es 4 Hertz

iii) La velocidad angular es aproximadamente 25.133

iv) La velocidad lineal es de aproximadamente 3,77 m / s

Explanation:

El radio de la rueda, r = 15 cm = 0,15 m

El número de vueltas que hace la rueda = 64 vueltas

El tiempo que tarda el volante en dar 64 vueltas = 16 segundos

i) El período = El tiempo que tarda la rueda en dar 1 vuelta

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El período de la rueda, T = 0,25 segundos

ii) La frecuencia = El número de vueltas por segundo

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La velocidad angular, ω ≈ 25.133

iv) La velocidad lineal, v = r × ω

∴ v = 0,15 m × 8 · π rad / segundos ≈ 3,77 m/s

La velocidad lineal, v ≈ 3.77 m/s

7 0
3 years ago
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