Question

An electromagnet produces a magnetic field of 0.520 T in a cylindrical region of radius 2.40 cm between its poles. A straight wire carrying a current of 10.5 A passes through the center of this region and is perpendicular to both the axis of the cylindrical region and the magnetic field.
What magnitude of force is exerted on the wire?

Answer 1

Answer:

Magnetic force, F = 0.262 N

Explanation:

It is given that,

Magnetic field of an electromagnet, B = 0.52 T

Length of the wire, $l = 2r =2\times 2.4=4.8\ cm=0.048\ m$

Current in the straight wire, i = 10.5 A

Let F is the magnitude of force is exerted on the wire. The magnetic force acting on an object of length l is given by :

$F=ilB$

$F=10.5\ A\times 0.048\ m\times 0.52\ T$

F = 0.262 N

So, the magnitude of force is exerted on the wire is 0.262 N.